Answer:
Output of the following program is :56
Explanation:
In the given code snippet, x is initialize with 5 and y is with 0.Then y=x++ statement will assign 5 to y and the increment the value of x,because x++ is a post increment operator.So the value of x will increase after this statement.First print statement will print the value of y i.e 5 and the next print statement will print the value of x i.e 6 without space.Therefore the Output will be 56.
Answer:
it's most prolly a bug.The game crashes a lot tbh
Answer:
True
Explanation:
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Answer:
#include<iostream>
#include<cmath>
using namespace std;
int main()
{
int a=1;
while(a==1){
float P=0.0,R=0.0,T=0.0,A=0.0,n=0.0,nt=0.0;
cout<<"Enter your Initial Investment Amount : ";
cin>>P;
cout<<"Enter your Rate of Annual interest : ";
cin>>R;
cout<<"Enter No. of times the interest is compound : " ;
cin>>n;
cout<<"Enter Time (years) : ";
cin>>T;
nt=n*T;
A=P*pow((1+R/n),(nt));
cout<<"After "<<T<<" years, the initial investment of "<<P<<" is : "<<A;
cout<<"\nEnter 1 to continue or exit by pressing any other button";
cin>>a;
}
return 0;
}
Explanation:
- Get the essential values from user as an input and store them in variables.
- Apply the following formulas to calculate years and initial investment.
- nt=n*T;
- A=P*pow((1+R/n),(nt));
- Finally display the results.
A computer data storage is made of many features. Set the Append Only property to YES to allow users to add data to a Long Text field but not to change or remove existing data.
- Append-only is known to be a characteristic or component of computer data storage. It is where new data can be appended to the storage, but where existing data is said to be immutable.
A field's data type is very essential property as it shows what kind of data the field can store.
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