Answer:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main()
{
int arr[100];
int i = 0;
int j = 0;
char c[10];
char temp;
int sum = 0;
FILE* fp;
if ((fp = fopen("test.txt", "r")) == NULL) {
printf("cannot open the file");
return;
}
else {
do {
temp = fgetc(fp);
if (temp == ' ' || temp == '\n') {
c[j] = '\0';
arr[i++] = atoi(c);
j = 0;
continue;
}
c[j++] = temp;
} while (temp != EOF);
for (j = i - 1; j >= 0; j--) {
printf("%d\n", arr[j]);
}
}
getchar();
}
Explanation:
Answer:
C. 40
Explanation:
The code uses IF and ELSE statements to carry execute a block of code if any of the statements hold true
OrderTotal here is greater than 100, and this allows the second IF ELSE block to be executed.
The code to be executed is discountAmount = OrderTotal * 0.2
This will be discountAmount = 200 *0.2
therefore, discountAmount = 40.
Ummm what is the question
Answer:
Option A is the correct answer.
Explanation:
Answer:
second_int = "Enter the second integer: "
usernum = int(input("Enter the first integer: "))
x = int(input(second_int))
usernum = usernum // x
print(usernum, end= ' ')
usernum = usernum // x
print(usernum, end= ' ')
usernum = usernum // x
print(usernum, end= ' ')
usernum = usernum // x
print(usernum)
Explanation:
im good
