How do you show your work on solving 4794 divided by 22

The residents of a city voted on whether to raise property taxes. The ratio of yes votes to no votes was to . If there were 12,7

Sever21 [200]

Answer: The question is incomplete

Step-by-step explanation: The answer to this question cannot be determined correctly since an important detail is missing.

However, let me explain how you would normally go about it by using an example of mine. If for example the ratio of yes votes to no votes was 8 to 5, and the question requires you to calculate how many yes votes were there as indicated in your question, then the first step would be to find the total number of both sides of the ratio. That is add 8 to 5 which gives you 13. This means if there was a total of 13 votes cast, every yes vote stands for 8 out of 13 votes and every no vote stands for 5 out of 13 votes.

To express it mathematically, every yes vote would be 8/13 of the total (12779) and every no vote would be 5/13 of the total (12779).

Therefore to determine how many yes votes there was, is calculated as follows;

Let yes votes be y and no votes be x'

y = (8/13) * 12779

y = 102232/13

y = 7864

Based on my example that the ratio of yes votes to no votes is 8 to 5,

Then the number of yes votes was 7,864.

7 0

3 years ago

A spinner has 5 sector's of equal size. The sectors are labeled 1,2,3,4, and 5. the spinner is spun twice.x is the number of tim

LuckyWell [14K]

Answer:

Because the sectors are of equal size, each sector has the same probability of happening.

So for every number, you have a probability of 0.2 of it appearing.

Because you have three odd numbers, the probability to land on an odd number on each spin is 0.6. You can also say that the probability to not have an odd number is 0.4.

So what is the probability to have 0 odd number in two spins?

What is the probability to have 1 odd number in two spins? You can have one odd number on the first or one odd on the second spin, that is why we add the probabilities.

What is the probability to have 2 odd numbers in two spins?

To verify if we did a good job, we add all the probabilities. We should get 1.

.

So to slide your bars, you slide them up to the number I gave you for each case.

Hope this helps!

8 0

3 years ago

^

love history [14]

Answer:

B. x < -1

Step-by-step explanation:

Hello!

Let's put them in order from greatest to least:

$\{-2,-5,-9,-12\}$

Given our possible inequalities, we need to find the inequality that contains all of these values.

The inequality that works is x < -1, as all values are less than -1.

Therefore, the answer is B. x < -1.

4 0

2 years ago

PLEASE HELP! Brainlest!!! Just fill in the chart

Cloud [144]

Answer:

Softball : Speed: 29.68 m/s --- Kinetic Energy: 82.36 Joules

Horse: Speed: 13.33 m/s --- Kinetic Energy: 48,331.40 Joules

Satellite: Speed: 3067.13 m/s --- Kinetic Energy: 3,762,910,000 Joules

I hope this helps! Please give me Brainliest. Sorry for the late response, my power went out.

4 0

3 years ago

Read 2 more answers

In a certain Algebra 2 class of 30 students, 19 of them play basketball and 12 of them play baseball. There are 8 students who p

Alenkinab [10]

Answer:

Probability that a student chosen randomly from the class plays basketball or baseball is $\frac{23}{30}$ or 0.76

Step-by-step explanation:

Given:

Total number of students in the class = 30

Number of students who plays basket ball = 19

Number of students who plays base ball = 12

Number of students who plays base both the games = 8

To find:

Probability that a student chosen randomly from the class plays basketball or baseball=?

Solution:

$P(A \cup B)=P(A)+P(B)-P(A \cap B)$ ---------------(1)

where

P(A) = Probability of choosing a student playing basket ball

P(B) = Probability of choosing a student playing base ball

P(A \cap B) = Probability of choosing a student playing both the games

Finding P(A)

P(A) = $\frac{\text { Number of students playing basket ball }}{\text{Total number of students}}$

P(A) = $\frac{19}{30}$ --------------------------(2)

Finding P(B)

P(B) = $\frac{\text { Number of students playing baseball }}{\text{Total number of students}}$

P(B) = $\frac{12}{30}$ ---------------------------(3)

Finding $P(A \cap B)$

P(A) = $\frac{\text { Number of students playing both games }}{\text{Total number of students}}$

P(A) = $\frac{8}{30}$ -----------------------------(4)

Now substituting (2), (3) , (4) in (1), we get

$P(A \cup B)= \frac{19}{30} + \frac{12}{30} -\frac{8}{30}$

$P(A \cup B)= \frac{31}{30} -\frac{8}{30}$

$P(A \cup B)= \frac{23}{30}$

7 0

3 years ago

How do you show your work on solving 4794 divided by 22​

How do you show your work on solving 4794 divided by 22