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andrew11 [14]
3 years ago
13

Can 12(x^3+y^2)+6(y^2+1) be the factored form of 12x^3+18y^2+6?

Mathematics
2 answers:
kirill [66]3 years ago
8 0

The correct answer is yes. just distribute 12 to all within first set then 6 to all in 2nd set then add like terms

Misha Larkins [42]3 years ago
4 0

Answer:

YES

Step-by-step explanation:

So how you can figure this out is you do the Distributive Property.

So it will be 12x^3+12y^2+6y^2+6.

The next thing you have to do is add together the ones that are similar which is 12y^2+6y^2 to get 18y^2.

Your answer is 12x^3+18y^2+6. So YES it can be factored into that form.

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Aleks04 [339]

For this case, the first thing we must do is define variables.

We have then:

x: altitude of the plane in feet

y: final temperature

The equation modeling the problem for this case is given by:

y = - \frac{1.1}{1000} x + 59.7

Thus, evaluating the function for x = 11,000 ft. Height we have:

y = - \frac{1.1}{1000} (11000) +59.7

y = 47.6

Answer:

the temperature at an altitude of 11,000 ft is 47.6 F

4 0
3 years ago
Read 2 more answers
Help pls this geometry killing me??!!!
kondaur [170]

Answer:

16

Step-by-step explanation:

The triangle AEC is a right triangle and 2 sides are already filled in.

The hypotenuse is 10 and one side is 6.

So, this is a 3-4-5 right triangle.

Thus, the remaining side EC is 8.

Since EC is congruent to ED, then segment CD is 8+8=16

4 0
3 years ago
A random sample of 169 observations is to be drawn from a population with a mean of 80 and a standard deviation of 39. find the
Drupady [299]
Mu=80, sigma=39, X=85
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8 0
2 years ago
What is the value of a1 of the geometric series? Sigma-Summation Underscript n = 1 Overscript infinity EndScripts 12 (negative o
worty [1.4K]

Answer:

12

Step-by-step explanation:

The given geometric series is

\sum_{n = 1}^{ \infty} 12( { -  \frac{1}{9} })^{n - 1}

We want to determine the first term of this geometric series.

Recall that the explicit formula is

a_{n} = 12( { -  \frac{1}{9} })^{n - 1}

To find the first term, we put n=1 to get:

a_{1} = 12( { -  \frac{1}{9} })^{1 - 1}

This gives us:

a_{1} = 12( { -  \frac{1}{9} })^{0}

a_{1} = 12(1) = 12

Therefore the first term is 12

6 0
3 years ago
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How to find standard deviation from true probability and sample size.
bixtya [17]

Answer:

I can even see anything can you reupload your answer, please?

Step-by-step explanation:

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