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andrew11 [14]
3 years ago
13

Can 12(x^3+y^2)+6(y^2+1) be the factored form of 12x^3+18y^2+6?

Mathematics
2 answers:
kirill [66]3 years ago
8 0

The correct answer is yes. just distribute 12 to all within first set then 6 to all in 2nd set then add like terms

Misha Larkins [42]3 years ago
4 0

Answer:

YES

Step-by-step explanation:

So how you can figure this out is you do the Distributive Property.

So it will be 12x^3+12y^2+6y^2+6.

The next thing you have to do is add together the ones that are similar which is 12y^2+6y^2 to get 18y^2.

Your answer is 12x^3+18y^2+6. So YES it can be factored into that form.

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Answer:

Step-by-step explanation:

Hello, we know that the z complex solutions of

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3 0
3 years ago
What is the solution to -4|-2x + 6| = -24?
Natalka [10]
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4 0
3 years ago
Read 2 more answers
784,072 rounded to the nearest hundred thousand
Fittoniya [83]

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Thus; if you apply this to your question:


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3 0
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