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kvv77 [185]
3 years ago
9

What is the domain of f(x) = 2|x − 1| + 3?

Mathematics
2 answers:
Wewaii [24]3 years ago
6 0

Answer:

<h2>The domain=3</h2>

Step-by-step explanation:

Nataly [62]3 years ago
5 0

Answer:

your answer will be option D) all real numbers

Step-by-step explanation:

have a nice day/night !! ^_^

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Steven wants to buy a $565 bicycle. Steven has no money saved. But will be able to deposit $30 into a savings account when he re
Nikitich [7]
565+65=630 so he needs that much to get the bike AND pay his sister back. 630 divided by $30 is 21. So, in 21 weeks, Steven Can pay back his sister and get the bike
5 0
3 years ago
Could u guys try this one out as well
Korolek [52]

Answer:

D) a reflection over the line x = 0 followed by a reflection over the line y = 0.

Step-by-step explanation:

In this problem, the original figure is in quadrant I (1) and the second image is in quadrant III (3).  In order for the figure to make this transition and be 'flipped' into the opposite direction of the original figure, a reflection would have to take place.  If triangle 'A' is reflected over the line y = x or y = -x, the orientation of the triangle would stay the same, meaning the point of the triangle would still face upward.  If you reflect over the line x = 0 and then again over the line x = 0 (as in C), your triangle would be in the same spot.  However, if you reflect triangle 'A' over x = 0, you would get a 'flipped image' into quadrant 4 and the orientation of the triangle would face downward.  Following this reflection by another reflection over the line y=0 would give you the mirror image in quadrant III (3).  So, D is the correct sequence of reflections.  

3 0
3 years ago
In circle R, RD(line over it) is a radius and DF (line over it) is a tangent segment which statement must be true?
butalik [34]
We'll have an attached picture (Ignore the labeling). We can easily observe that DF (in the picture BC), cannot be equal to the radius. Then, we cannot also claim that RD=RF. And since we are talking about the tangent segment, we'll have a right triangle. The correct answer is C)

5 0
3 years ago
For the following exercises, solve each inequality and write the solution in interval notation.
WARRIOR [948]

Answer:

The solution to the inequality |x-2|>10 in interval notation is given by -8<x<12

Step-by-step explanation:

An absolute value inequality |x-2|>10 is given.

It is required to solve the inequality and write the solution in interval form.

To write the solution, first solve the given absolute value inequality algebraically and then write it in interval notation.

Step 1 of 2

The given absolute value inequality is $|x-2|>10$.

The inequality can be written as

x-2<10 and x-2>-10

First solve the inequality, x-2<10.

Add 2 on both sides,

x-2<10

x-2+2<10+2

x<12

Step 2 of 2

Solve the inequality x-2>-10.

Add 2 on both sides,

x-2>-10

x-2+2>-10+2

x>-8

The solution of the inequality in interval notation is given by -8<x<12.

7 0
2 years ago
Simplify the following expression.<br><br><br> 3^11/5 / 3^-9/5
Bess [88]

Answer:

81

Step-by-step explanation:

\frac{3^{11/5}}{3^{-9/5}}  can be written as 3^{11/5} × 3^{9/5}

= 3^{20/5}

=3^4

= 81

8 0
2 years ago
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