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Cerrena [4.2K]
3 years ago
8

WILL GIVE BRAINLIEST!!!

Chemistry
1 answer:
Afina-wow [57]3 years ago
4 0

Answer:

0.373 moles of ammonium carbonate

Explanation:

To solve this question we must find the molar mass of ammonium carbonate. With the molar mass and the mass we can find its moles, as follows:

(NH₄)₂CO₃ contains: 2 moles N, 8 moles H, 1 mole C, 3 moles O. Molar mass:

2N = 14.0g/mol*2 = 28.0

8H = 1.0g/mol*8 = 8.0

1C = 12.0g/mol*1 = 12.0

3O = 16.0g/mol*3 = 48.0

Molar mass: 28.0 + 8.0 + 12.0 + 48.0 = 96.0g/mol

The moles of ammonium carbonate in 35.8g are:

35.8g * (1mol / 96.0g) =

<h3>0.373 moles of ammonium carbonate</h3>
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(Please help will mark brainliest!)
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We know that Weighted atomic mass of Element is Calculated based upon their existence of isotopes and the Relative abundance of these isotopes.

Given that the Element X is Composed of :

Isotope                       Relative abundance                   Atomic Mass

⁵⁵X                                        70%                                               55

⁵⁶X                                        20%                                               56

⁵⁷X                                        10%                                                57

Weighted Atomic Mass of Element X :

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= 38.50 + 11.2 + 5.70

= 55.4

So, the Weighted Atomic Mass of Element X is 55.4

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https://youtu.be/3zmeVamEsWI

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