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3 years ago

WILL GIVE BRAINLIEST!!!

Chemistry

1 answer:

Afina-wow [57]3 years ago

4 0

Answer:

0.373 moles of ammonium carbonate

Explanation:

To solve this question we must find the molar mass of ammonium carbonate. With the molar mass and the mass we can find its moles, as follows:

(NH₄)₂CO₃ contains: 2 moles N, 8 moles H, 1 mole C, 3 moles O. Molar mass:

2N = 14.0g/mol*2 = 28.0

8H = 1.0g/mol*8 = 8.0

1C = 12.0g/mol*1 = 12.0

3O = 16.0g/mol*3 = 48.0

Molar mass: 28.0 + 8.0 + 12.0 + 48.0 = 96.0g/mol

The moles of ammonium carbonate in 35.8g are:

35.8g * (1mol / 96.0g) =

<h3>0.373 moles of ammonium carbonate</h3>

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A 100 gram glass container contains 200 grams of water and 50.0 grams of ice all at 0°c. a 200 gram piece of lead at 100°c is ad

ASHA 777 [7]

$0 \; \textdegree{\text{C}}$

Explanation:

Assuming that the final (equilibrium) temperature of the system is above the melting point of ice, such that all ice in the container melts in this process thus

$E(\text{fusion}) = m(\text{ice}) \cdot L_{f}(\text{water}) = 66.74 \; \text{kJ}$ and
$m(\text{water, final}) = m(\text{water, initial}) + m(\text{ice, initial}) = 0.250 \; \text{kg}$

Let the final temperature of the system be $t \; \textdegree{\text{C}}$ . Thus $\Delta T (\text{water}) = \Delta T (\text{beaker}) = t(\text{initial}) - t_{0} = t \; \textdegree{\text{C}}$

$Q(\text{water}) &= &c(\text{water}) \cdot m(\text{water, final}) \cdot \Delta T (\text{water})= 1.047 \cdot t\; \text{kJ}$ (converted to kilojoules)
$Q(\text{container}) &= &c(\text{glass}) \cdot m(\text{container}) \cdot \Delta T (\text{container})= 0.0837 \cdot t \; \text{kJ}$
$Q(\text{lead}) &= &c(\text{lead}) \cdot m(\text{lead}) \cdot \Delta T (\text{lead})= 0.0255 \cdot (100 - t)\; \text{kJ}$

The fact that energy within this system (assuming proper insulation) conserves allows for the construction of an equation about variable $t$ .

$E(\text{absorbed} ) = E(\text{released})$

$E(\text{absorbed} ) = E(\text{fushion}) + Q(\text{water}) + Q(\text{container})$
$E(\text{released}) = Q(\text{lead})$

Confirm the uniformity of units, equate the two expressions and solve for $t$ :

$66.74 + 1.047 \cdot t + 0.0837 \cdot t = 0.0255 \cdot (80 - t)$

$t \approx -55.95\; \textdegree{\text{C}} < 0\; \textdegree{\text{C}}$ which goes against the initial assumption. Implying that the final temperature does <em>not</em> go above the melting point of water- i.e., $t \le 0 \; \textdegree{\text{C}}$ . However, there's no way for the temperature of the system to go below $0 \; \textdegree{\text{C}}$ ; doing so would require the removal of heat from the system which isn't possible under the given circumstance; the ice-water mixture experiences an addition of heat as the hot block of lead was added to the system.

The temperature of the system therefore remains at $0 \; \textdegree{\text{C}}$ ; the only macroscopic change in this process is expected to be observed as a slight variation in the ratio between the mass of liquid water and that of the ice in this system.

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3 years ago

NADH is also used by cells when making certain molecules. Based on your knowledge of the role of NADH in cellular respiration, w

OLEGan [10]

Answer:

Reducing molecules.

Explanation:

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The NADH molecule is used as the reducing molecule in the biosynthesis of the different reaction. The NADH molecule reduces its hydrogen ions and also carry electrons for the synthesis of molecules. The NADH molecule is also used in the shuttle system as well.

Thus, the answer is reducing molecules.

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3 years ago

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galben [10]

Answer:

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Can somebody plz help answer this science questions (only 1-2 sentences is good thx !

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katen-ka-za [31]

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