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Law Incorporation [45]
2 years ago
8

I don’t understand what to do on these question, some help would be nice (trigonometry)

Mathematics
1 answer:
Bumek [7]2 years ago
8 0

Step-by-step explanation:

> find the angle of center circle:

cos~¹ 5/(5+12) = cos~¹ 5/17 = 72°

so the sector area of the shaded

region =

(360-72)/360 × 3.14 × 5²

= 288/360 × 78.5

= 62.8

> the height of triangle (red Line) =

4×tan 72° = 4× 3.078 = 12.31

the height of pyramid (green

Line) = √12.31²-8.5² =√74.16

= 8.61

so the volume of pyramid =

⅓×(17×8)×8.61 = 390.32

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3 years ago
Plz, help ASAP!!!!!!<br> WILL MARK BRAINLIEST IF YOUR ANSWER IS CORRECT!!!!!!
Mekhanik [1.2K]

Blank 1: Given

Blank 2 : AD is parallel to BC

Blank 3: <3≅<2

Blank 4: Transitive property of convergence

Blank 5: Definition of Bisect

Step-by-step explanation:

We need to fill in the blanks from the given options.

Blank 1:

ABCD is a parallelogram

This is given

So, blank 1: Given

Blank 2:

A parallelogram have parallel sides i.e in the given parallelogram AD is parallel to BC and AB is parallel to DC

So, Blank 2 : AD is parallel to BC

Blank 3:

We are given <3≅<2

So, Blank 3: <3≅<2

Blank 4:

We know, <1≅<3 and <3≅<2 using transitive property (A≅B and B≅C then A≅C)

So, <1 ≅ <2 is due to transitive property of convergence

Blank 4: Transitive property of convergence

Blank 5:

DC bisects <ADE

A bisect is an line or angle that divides into exactly two parts.

So, Blank 5: Definition of Bisect

Keywords: parallelogram, bisection

Learn more about parallelogram at:

  • brainly.com/question/13063819
  • brainly.com/question/3617539

#learnwithBrainly

4 0
3 years ago
I need an answer asap
allsm [11]

Answer:

yes

no

no

yes

Step-by-step explanation:

8 0
3 years ago
16pts for help with this math question
diamong [38]
Y=76 x-18
should be the anwer.
6 0
3 years ago
Read 2 more answers
Sorry I suck at math do u get this one
maks197457 [2]

Answer:

Number one will be 11 minutes

Number two will be 525 words

Step-by-step explanation:

7 0
2 years ago
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