How many moles are in 24.75 g of H2O? What is given the conversation and the unknown?
1 answer:
Answer:
1.373 mol H₂O
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
24.75 g H₂O
<u>Step 2: Identify Conversions</u>
Molar Mass of H - 1.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol
<u>Step 3: Convert</u>
<u /> = 1.37347 mol H₂O
<u>Step 4: Check</u>
<em>We are given 4 sig figs. Follow sig fig rules and round.</em>
1.37347 mol H₂O ≈ 1.373 mol H₂O
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Answer:
(4,20)
Explanation:
Oxygen di-fluoride or OF2 is a polar molecule, formed through the covalent bonding between one Oxygen and two Fluorine atoms.
Oxygen has atomic no. 8 and its electronic configuration is as below:
- 1s^2, 2s^2, 2p^4
Oxygen has 4 electrons in the valence shell. It has the ability to share two electrons with other atoms through covalent bond and get stable.
The atomic number of Fluorine is 7, and its electronic configuration is as:
- 1s^2, 2s^2, 2p^5
So, Fluorine atom has the capacity to accept 1 electron to form 1 covalent bond or in the formation of the F- ion.
The structure of OF2 is a bent structure with O atom sandwiched by two fluorine atoms like F-O-F. So there are two electrons on oxygen atom that are taking part in the formation of covalent bond with each Fluorine atom (Please dot structure in figure).
Now we can easily calculate no of bonding and non-bonding electrons.
- No. of bonding electrons = 4 (two from oxygen and two from fluorine atoms each)
- No. of non-bonding electrons= 20 (6+6 from two Fluorine atoms and 6 from Oxygen atom)
Hope it helps! :)
