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NikAS [45]
3 years ago
14

A car with a mass of 1,100 kg is moving with a velocity of 30 m/s due east . What is the moment?

Chemistry
1 answer:
dexar [7]3 years ago
6 0
Momentum = (mass) x (velocity) = (1,100) x (30) =

33,000

kg-m/sec due east

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Glucose (C6H12O6) can be fermented to yield ethanol (CH3CH2OH) and carbon dioxide (CO2). C6H12O6⟶2CH3CH2OH+2CO2 The molar mass o
jekas [21]

Answer:

The % yield is 74.45 %

Explanation:

<u>Step 1:</u> The balanced equation

C6H12O6⟶2CH3CH2OH+2CO2

<u>Step 2</u>: Data given

Molar mass glucose = 180.15 g/mol

Molar mass of ethanol = 46.08 g/mol

Molar mass of carbon dioxide = 44.01 g/mol

Mass of glucose = 61.5 grams

Mass of ethanol = 23.4 grams

<u>Step 3:</u> Calculate moles of glucose

Moles glucose = Mass glucose  / Molar mass of glucose

Moles glucose = 61.5 grams / 180.15 g/mol

Moles glucose = 0.341 moles

<u>Step 4:</u> Calculate moles of ethanol

1 mole of glucose consumed, produces 2 moles of ethanol and 2 moles of CO2

0.341 moles of glucose, will produce 2*0.341 = 0.682 moles of ethanol

<u>Step 5:</u> Calculate mass of ethanol

Mass ethanol = moles ethanol * Molar mass ethanol

Mass ethanol = 0.682 moles * 46.08 g/mol

Mass ethanol = 31.43 grams = theoretical mass

<u>Step 6:</u> Calculate % yield

% yield = actual mass / theoretical mass

% yield = (23.4 grams / 31.43 grams) * 100%

% yield = 74.45 %

The % yield is 74.45 %

7 0
3 years ago
Liquid helium boils at –268.93 °C. What is the boiling point of helium on the Kelvin temperature scale?
BARSIC [14]

In order to change celcius to kelvin always add 73 to it leaving you with -195.93

4 0
3 years ago
Read 2 more answers
39. Consider the following molecules:
sweet [91]
I) cc14
ii) h20
iii) i’m not sure

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5 0
3 years ago
The climate of the continental United States is generally _____________.
rodikova [14]
The answer is B. Temperate.
3 0
3 years ago
How many grams of NaOH are produced from 1.20 x 10^2 of Na2O
oksian1 [2.3K]
Write an balance the equation

Na2O + H2O -> 2 NaOH

Calculate the molecular mass of Na2O and NaOH from the atomic mass from the periodic table.

Na = 23
O=16
H=1

Na2O = 23 * 2 + 16 = 62
NaOH = 23+16+1= 40

For the stoichiometry of the reaction one mole of Na2O = 62g produce two mol of NaOH = 2* 40= 80 g

120 g Na2O x 80g NaOH / 62g Na2O=

154.8 g NaOH
5 0
3 years ago
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