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4 years ago

6

C12H7Cl3FNaO2 what are them elements in that chemical formula

1 answer:

LuckyWell [14K]4 years ago

8 0

Assuming you are asking for the names of the elements in that formula , the answer is

carbon
hydrogen
chlorine
fluorine
sodium
oxygen

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The alkali metals all react with water. which is the most reactive metal?

kifflom [539]

Alkali Metals (Group 1) elements experience an increase in the vigour of their reaction in water as they go down the group (as the atomic number increase). As such the most reactive Alkali Metal would be FRANCIUM, which is at the base of Group One.

Quite frankly, you do not want Francium to react with water- that's a huge explosion on your hand.

8 0

3 years ago

earnstyle [38]

Answer:
Cp = 0.093 J.g⁻¹.°C⁻¹
Solution:

The equation used for this problem is as follow,

Q = m Cp ΔT ----- (1)

Where;
Q = Heat = 300 J

m = mass = 267 g

Cp = Specific Heat Capacity = ??

ΔT = Change in Temperature = 12 °C

Solving eq. 1 for Cp,

Cp = Q / m ΔT

Putting values,
Cp = 300 J / (267 g × 12 °C)

Cp = 0.093 J.g⁻¹.°C⁻¹

6 0

3 years ago

¿soy guapo?<br> si dices que si te doy una galletita

tankabanditka [31]

Answer:

Hindi ko po ma gets sinasabi nyu pwedeng pakiayus

8 0

3 years ago

Read 2 more answers

You dissolve 8.65 grams of lead(l) nitrate in water and then you add 2 50 grams of aluminum. This reaction occurs 2AI(S)+ 3Pb(NO

olga55 [171]

<u>Answer:</u> The theoretical yield of solid lead comes out to be 5.408 grams.

<u>Explanation:</u>

To calculate the moles, we use the following equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

<u>Moles of Lead nitrate:</u>

Given mass of lead nitrate = 8.65 grams

Molar mass of lead nitrate = 331.2 g/mol

Putting values in above equation, we get:

$\text{Number of moles}=\frac{8.65g}{331.2g/mol}=0.0261moles$

<u>Moles of Aluminium:</u>

Given mass of aluminium = 2.5 grams

Molar mass of aluminium = 27 g/mol

Putting values in above equation, we get:

$\text{Number of moles}=\frac{2.5g}{27g/mol}=0.0925moles$

For the given chemical reaction, the equation follows:

$2AI(s)+3Pb(NO_3)_2(aq.)\rightarrow 3Pb(s)+2AI(NO3)_3(aq.$

By Stoichiometry:

3 moles of lead nitrate reacts with 2 moles of aluminium

So, 0.0261 moles of lead nitrate are produced by = $\frac{2}{3}\times 0.0261=0.0174moles$ of aluminium.

As, the required amount of aluminium is less than the given amount. Hence, it is considered as the excess reagent.

Lead nitrate is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

3 moles of lead nitrate are produces 3 moles of lead metal.

So, 0.0261 moles of lead nitrate will produce = $\frac{3}{3}\times 0.0261=0.0261moles$ of lead metal.

Now, to calculate the grams or theoretical yield of lead metal, we put in the mole's equation, we get:

Molar mass of lead = 207.2 g/mol

Putting values in above equation, we get:

$0.0261mol=\frac{\text{Given mass}}{207.2g/mol}$

Mass of lead = 5.408 grams

Hence, the theoretical yield of solid lead comes out to be 5.408 grams.

8 0

3 years ago

Which is the balanced equation for:<br> Al2O3 + Fe – Fe3O4 + AL

Sloan [31]

Answer:

4Al203 + 9Fe -> 3Fe3O4 + 8Al

Amount of Al on reactant side: 8

Amount of Al on product side: 8

Amount of O on reactant side: 12

Amount of O on product side: 12

Amount of Fe on reactant side: 9

Amount of Fe on product side: 9

6 0

3 years ago