The 15th term of the arithmetic sequence 
Option B is correct
The nth term of an arithmetic sequence is given as:
The first value, a = 22
Since 
The common difference, d = 3
The 15th term of the arithmetic sequence = 64
Learn more here: brainly.com/question/24072079
Answer:
vertical compression of One-half, horizontal stretch to a period of 4 pi, vertical shift of 1 unit up, phase shift of Pi units left
Step-by-step explanation:
Answer:
5/4k^2
Step-by-step explanation:
P=5\dfrac{k}{6}\times \dfrac{3}{2k^3}.
We will be using the following property of exponents:
\dfrac{a^x}{a^y}=a^{x-y}.
We have
P\\\\\\=5\dfrac{k}{6}\times\dfrac{3}{2k^3}\\\\\\=\dfrac{5}{6}\times\dfrac{3}{2}k^{1-3}\\\\\\=\dfrac{5}{4}k^{-2}=\dfrac{5}{4k^2}.
Thus, the required product is \dfrac{5}{4k^2}.
Read more on Brainly.com - brainly.com/question/8858421#readmore
Answer:
70
Step-by-step explanation:
100 - 2(x + 5) = 100 - 2x - 10 = 90 -2x
90 - 2x
90 - 2×10
90 - 20 = 70
This would be C. 60$
This is because if she got the bag for 50% off, 30 divided by 2 is 15$, 45 divided by 2 is 22.5, 60 divided by 2 is 30$ so option C. Would be your answer.
