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xz_007 [3.2K]
3 years ago
13

Ed has 4 cards.

Mathematics
1 answer:
kumpel [21]3 years ago
8 0

Answer:

7

Step-by-step explanation:

Let's call the missing card number "x".

The mean is the sum divided by the number of elements, so we know that:

\frac{12 + 6 + 15 + x}{4} = 10\\~\\12 + 6 + 15 + x = 40\\33 + x = 40\\x = 7

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Solve 4 over x minus 4 equals the quantity of x over x minus 4, minus four thirds for x and determine if the solution is extrane
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I'm thinking this is what the problem looks like: \frac{4}{x-4}= \frac{x}{x-4}- \frac{4}{3}.  The first thing to do is to move the \frac{x}{x-4} over to the other side because it has a common denominator with the other side.  Doing that and at the same time combining them over their common denominator looks like this: \frac{4-x}{x-4}= -\frac{4}{3}.  The best way to solve for x now is to cross-multiply to get 3(4-x)=-4(x-4).  Distributing through the parenthesis is 12 - 3x = -4x + 16.  Solving for x gives us x = 4.  Of course when we sub a 4 back in for x we get real problems, don't we?  Dividing by zero breaks every rule in math that there ever was! So, yes, the solution is extraneous.
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Question 9
vagabundo [1.1K]

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6.9 miles.

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3 years ago
Please help in the question it should be if t=-6 when r =-2 its an error
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Answer:

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Step-by-step explanation:

Given that r varies inversely as t , then the equation relating them is

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