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Helen [10]
3 years ago
10

Please help me thank you

Mathematics
1 answer:
Ainat [17]3 years ago
3 0

Step-by-step explanation:

X= 2, y= -6

X= 0, y= 0

X= -2, y= 6

X= -4, y= 12

X= - 7, y= 21

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I can help you write one
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If the circumference of a basketball is 29.5 inches, how many centimeters is the circumferenceof a basketball? Round your answer
Solnce55 [7]

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75 cm

Step-by-step explanation:

Every inch is 2.54 cm, so 29.5 in=74.93 cm. 74.93 rounded to the nearest whole is 75cm.

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The yearbook club had a meeting. The meeting had 21 people, which is one-third of the club. How many people are in the club?
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Answer:

63 because if 1/3 of the club is gone then we need to multiply 21 times 21 to find the total. Which is 63.

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Click the picture that I sent you
Digiron [165]

Answer: 1211.6585 years

<u>Step-by-step explanation:</u>

The equation for exponential growth is: P=P_oe^{kt}

  • P: final population
  • P₀: initial population
  • k: rate of decay (or growth)
  • t: time

Use the half life information to find k:

\dfrac{1}{2}P_o=P_oe^{k(800)}\\\\\\\dfrac{1}{2}=e^{800k}\qquad \rightarrow \qquad \text{divided both sides by}\ P_o\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=800k\qquad \rightarrow \qquad \text{applied ln to both sides}\\\\\\\dfrac{ln(\frac{1}{2})}{800}=k\qquad \rightarrow \qquad \text{divided both sides by 800}\\\\\\\large\boxed{-0.000867=k}

Next, input the information (65% decayed = 35% remaining) and the k-value to find your answer.

.35P_o=P_oe^{-0.000867t}\\\\\\.35=e^{-0.000867t}\\\\\\ln(.35)=-0.000867t\\\\\\\dfrac{ln(.35)}{-0.000867}=t\\\\\\\large\boxed{1211.6585=t}

5 0
3 years ago
If m&lt;BEG = (19x + 3)° and m&lt;EGC = (m&lt;GCB + 4x)°, which of the following statements is true about quadrilateral BEGC? Se
viktelen [127]

Answer:

The sum of all exterior angles of BEGC is equal to 360° ⇒ answer F only

Step-by-step explanation:

* Lets revise some facts about the quadrilateral

- Quadrilateral is a polygon of 4 sides

- The sum of measures of the interior angles of any quadrilateral is 360°

- The sum of measures of the exterior angles of any quadrilateral is 360°

* Lets solve the problem

- DEGC is a quadrilateral

∵ m∠BEG = (19x + 3)°

∵ m∠EGC = (m∠GCB + 4x)°

∵ The sum of the measures of its interior angles is 360°

∴ m∠BEG + m∠EGC + m∠GCB + m∠CBE = 360

∴ (19x + 3) + (m∠GCB + 4x) + m∠GCB + m∠CBE = 360 ⇒ add the like terms

∴ (19x + 4x) + (m∠GCB + m∠GCB) + m∠CBE + 3 = 360 ⇒ -3 from both sides

∴ 23x + 2m∠GCB + m∠CBE = 375

∵ The sum of measures of the exterior angles of any quadrilateral is 360°

∴ The statement in answer F is only true

3 0
4 years ago
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