Answer:
<u>Given</u>
and
<em>See the graphs attached</em>
To draw the graphs follow the rules we described in the previous questions.
- 1. Identify x-intercept and y-intercept and connect them to have the line.
- 2. Shade the region above or below the line for the inequality.
We see the only difference the expressions have is the equation or inequality symbols.
- Equation symbol means the graph of the equation is a line.
- Inequality symbol means the graph of this is a region above the same line, in our case the line is not a part of the covered region because it is "<".
We can state that the inequality excludes the line and includes only the region above the same line.
The answer is D, 10 is in the thousandths place
Answer:
Step-by-step explanation:
Figure (1)
x° = 107° [Vertically opposite angles]
Since, vertical angles are equal in measure.
Figure (2)
x + 71° = 90° [Given, complementary angles]
x = 90° - 71°
x = 19°
Figure (3)
x + 21° = 180° [Given as supplementary angles]
x = 180° - 21°
x = 159°
Figure (4)
x = 129° [Vertical angles]
Figure (5)
x° = 90° [Given]
z° + 34° = 90°
z° = 90° - 34°
z° = 56°
Since, x° + y° + z° = 180° [Linear angles]
90° + y° + 56° = 180°
y° + 146° = 180°
y° = 180° - 146°
y° = 34°
Answer:

Step-by-step explanation:
Let x be the number of helium balloons they can buy
- Write it out: 35 + 3.50x = 125
- Subtract 35 from each side, so it now looks like this: 3.50x = 90
- Divide each side by 3.50 to cancel out the 3.50 next to x. It should now look like this: x =
I hope this helps!
This is a hypergeometric distribution problem.
Population (N=50=W+B) is divided into two classes, W (W=20) and B (B=30).
We calculate the probability of choosing w (w=2) white and b (b=5) black marbles.
Hypergeometric probability gives
P(W,B,w,b)=C(W,w)C(B,b)/(C(W+B,w+b)
where
C(n,r)=n!/(r!(n-r)!) the number of combinations of choosing r out of n objects.
Here
P(20,30,2,5)
=C(20,2)C(30,5)/(20+30, 2+5)
=190*142506/99884400
=0.2710
Alternatively, doing the combinatorics way:
#of ways to choose 2 from 20 =C(20,2)
#of ways to choose 5 from 30=C(30,5)
total #of ways = C(50,7)
P(20,30,2,5)=C(20,2)*C(30,5)/C(50,7)
=0.2710
as before.