Answer:
A) zeros are x = ½ or x = ½
B) >> sum of zeros = (-Coefficient of x)/(Coefficient of x²)
>> Product of the zeros = Constant term/Coefficient of x²
Step-by-step explanation:
To find the zeros, we will equate the polynomial to zero.
Thus;
4x² - 4x + 1 = 0
Using quadratic equation, we can find the zeros.
x = [-(-4) ± √((-4)² - (4 × 4 × 1))]/(2 × 4)
x = (4 ± 0)/8
x = 4/8 and x = 4/8
Thus, zeros are x = ½ or x = ½
Now, to find the relationships between its zeroes and coefficients;
Sum of zeroes = ½ + ½ = 1
This is equal to -b/a = -(-4)/4 = 1.
Thus;
sum of zeros = (-Coefficient of x)/(Coefficient of x²)
Product of zeros = ½ × ½ = ¼
c/a = 1/4
This is equal to the product of the zeros.
Thus;
Product of the zeros = Constant term/Coefficient of x²
