Let present age of women be x.
Then,Present age of her daughter be y.
According to the question,
<u>Two years ago,</u>
Woman age = x - 2
Her daughter age = y - 2
Woman was 7 times old as her daughter. [ Given ]
x - 2 = 7 ( y - 2 )
=> x - 2 = 7y - 14
=> x - 2 + 14 = 7y
=> x + 12 = 7y ....( i )
<u>A</u><u>f</u><u>t</u><u>e</u><u>r</u><u> </u><u>Three years </u>,
Woman age = x + 3
Her daughter age = y + 3
she would be 4 times old as the girl. [ Given ]
x + 3 = 4 ( y + 3 )
=> x + 3 = 4y + 12
=> x = 4y + 12 - 3
=> x = 4y + 9....( ii (
Now,
★ Putting the value of x = 4y + 9 from equation ( ii ) in equation ( i ),we get
x + 12 = 7y
=> 4y + 9 + 12 = 7y
=> 21 = 7y - 4y
=> 21 = 3y
=> 3y = 21
=> y = 21/3
=> y = 7
And,
x = 4y + 9
★ Putting the value of y in equation ( ii ), we get
x = 4 × 7 + 9
x = 28 + 9
x = 37
Hence, the present age of women is 37 years and her daughter age is 7.
| u | = √(2² + (-1²)) = √5
| v | = √ ( 1² + (-8)² = √65
cos (u,v) = ( u * v ) / (| u | * | v |) =
(2 * 1 + ( -1 ) * ( - 8 )) / √5 √ 65 = (2 + 8) / √5 √65 = 10 / (√5 √ 65 )
The length of a larger diagonal:
d 1² = | u |² + 2 |u| |v| + | v |² = 5 + (2 √5 √65 * 10 / √5 √65 )+65
d 1² = 70 + 20 = 90
d 1 = √ 90 = 3√10
d 2² = 70 - 20 = 50
d 2 = √50 = 5√2
Answer:
The lengths of the diagonals are: 3√10 and 5√2 .
Answer:
7 : 1
Step-by-step explanation:
Paul's car goes 40 kilometers on 7 tanks.
Distance : Tanks
49 : 7
Fuel efficiency means the distance traveled by the car in one tank.
Therefore, we will reduce the ratio by dividing both sides by 7.
Distance : Tanks
: 
7 : 1
Therefore, car's fuel efficiency is 7 kilometers in one tank or the ratio between Distance traveled and fuel tanks is 7 : 1.
Answer:
7z
Step-by-step explanation:
4z-(-3z).
Two negatives equal a positive only <u>when they are right next to each other.</u>
4z+3z=7z. Hope this helps :D