Use slader, all you have to do is type up your workbook and question. And I would answer but I’m also testing for school right now. But go use it,
Answer:
0.9009
Step-by-step explanation:
Let X be the event that Current will flow
Let Y be the event that the first relay which is 1 is closed
Thus, we can say that every element of Y is in X, but X possesses more elements. Thus, Y ⊂ X.
Thus, we can say that;
P(X ∩ Y) = P(Y)
Thus, given that current flowed, the probability that relay 1 functioned will be expressed as;
P(Y | X) = (P(Y ∩ X))/P(X)
From earlier, we saw that P(X ∩ Y) = P(Y). Thus;
P(Y | X) = P(Y)/P(X)
From the question, P(Y) = 0.9
Since there are 3 relays, then we have;
P(X) = 1 - 0.1³ = 0.999
Thus;
P(Y | X) = 0.9/0.999
P(Y | X) = 0.9009
Answer: -6x² + 15x + 5
Step-by-step explanation:
To solve this problem, you only need to substitute g(x)'s equation as the value of the x in f(x), then simplify.
Step 1: f(x) = -3(2x² - 5x - 1) + 2
Step 2: Apply the distributive property
-3(2x²) + -3(-5x) + -3(-1)
-6x² + 15x + 3
Step 3: Simplify
f(x) = -6x² + 15x + 3 + 2
f(x) = -6x² + 15x + 5
okokok
Step-by-step explanation:
Answer:
There is a loss of 2 yards.
Step-by-step explanation:
To find the overall gain or loss, we add or subtract there values.
Initially, we have 0 yards.
Records 14, so 0 + 14 = 14, that is, for now a gain of 14
Then loses 7, so 14 - 7 = 7, for now a gain of 7.
Then, 7 - 9 = - 2, so in all, there is a loss of 2 yards.
