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LenKa [72]
2 years ago
9

PLS HELP WHAT ARE THESE TWO ILL GIVE BRAINLESS AND SHOW UR WORK

Mathematics
1 answer:
Hitman42 [59]2 years ago
3 0

Answer:

2) C

3) 62 degrees

Step-by-step explanation:

72+46=118

180-118

Hope this helps

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Simplify the expression 5+4+2(-3)+7+(-5)
liberstina [14]
Just use pemdas
(Parenthesis, exponents, multiplication, division, addition, subtraction)
4 0
3 years ago
The lengths of the sides of a triangle are 5, 12, and 13. What is the length of the altitude drawn to the side with length equal
mario62 [17]

Answer:  using  A= bh/2   THe height is 9.23

Step-by-step explanation:  First, with the Right Angle at the bottom, usr the sides to compute the area:  12*5=60

THen Imagine the side=13 as the base, so you have  b=13 for the formula

use the formula A= bh/2

60 = 13h/2 ==> 2(60) =13h --> 120/13 = h

h = 9.23

5 0
3 years ago
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Find each quotient and express it in rectangular form.
uranmaximum [27]

Answer:

A. thats the answer

Step-by-step explanation:

carry on learning

4 0
2 years ago
Suppose in the population, the Anger-Out score for men is two points higher than it is for women. The population variances for m
tatuchka [14]

Answer:

a)= 2

b) 6.324

c) P= 0.1217

Step-by-step explanation:

a) The mean of the sampling distribution of X`1- X`2 denoted by ux`-x` = u1-u2 is equal to the difference between population means i.e = 2 ( given in the question)

b) The standard deviation of the sampling distribution of X`1- X`2 ( standard error of X`1- X`2) denoted by σ_X`1- X`2 is given by

σ_X`1- X`2 = √σ²/n1 +σ²/n2

Var ( X`1- X`2) = Var X`1 + Var X`2 =  σ²/n1 +σ²/n2

so

σ_X`1- X`2 =√20 +20 = 6.324

if the populations are normal the sampling distribution X`1- X`2 , regardless of sample sizes , will be normal with mean u1-u2 and variance σ²/n1 +σ²/n2.

Where as Z is normally distributed with mean zero and unit variance.

If we take X`1- X`2= 0 and u1-u2= 2  and standard deviation of the sampling distribution = 6.324 then

Z= 0-2/ 6.342= -0.31625

P(-0.31625<z<0)= 0.1217

The probability would be 0.1217

8 0
2 years ago
The product of two positive consecutive odd integers is 2703. What are the positive numbers?
liberstina [14]

Answer:

The positive numbers are 51 and 53

Step-by-step explanation:

Let first odd integer be x and another odd integer is (x+2).

According to the given condition,

The product of two positive consecutive odd integers is 2703 i.e.

x(x+2) = 2703

x^2+2x-2703=0

It is a quadratic equation. It can be solved as follows :

x = 51 and x = -53

Neglecting negative sign,

The first number = 51

Another number =(51+2) = 53

Hence, the positive numbers are 51 and 53.

7 0
3 years ago
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