All categories

3 years ago

URGENT! Are these congruent? If so by which theorem

Mathematics

1 answer:

timurjin [86]3 years ago

8 0

Answer:

They are congruent by the AAS theorem!

Step-by-step explanation:

Sides EF and HJ are congruent, angles E and J are congruent and angles EGF and HGJ are congruent because they are vertical angles. Therefore, the triangles are congruent by the AAS theorem!

Hope this helps you :)

You might be interested in

I need help!<br> I need this today!

larisa [96]

Answer:

Yes.

Step-by-step explanation:

It is because 75=9

Hope This Helps.:)

3 0

2 years ago

Delta Math:<br> Finding Angles (Level 1) 1/5<br> Full explanation please<br> will give brainlist

olga nikolaevna [1]

Answer:

$m\angle FGC =101\degree$

Step-by-step explanation:

$m\angle CBF = 46\degree$ (Given)

$m\angle FIG = 55\degree$ (Given)

$m\angle IFG = m\angle CBF$ (Corresponding angles)

$\implies m\angle IFG = 46\degree$

$m\angle FGC =m\angle IFG+ m\angle FIG$

(By exterior angle theorem)

$m\angle FGC =46\degree+ 55\degree$

$m\angle FGC =101\degree$

4 0

2 years ago

What are the slope and why intercept shown on the graph below

viktelen [127]

Hello!

Let's start by finding the slope of the line. You can calculate the slope by dividing the change in y-values by the change in x-values using the following formula:

$\frac{ y_{1}- y_{2} }{ x_{1} - x_{2} }$

The plotted coordinates are (0, 5) and (4, -5); let's plug those into the formula:

$\frac{5(-5)}{0-4}$

Simplify:

$\frac{5+5}{-4}$

$\frac{10}{-4}$

$\frac{-5}{2}$

The slope is $\frac{-5}{2}$ .

Now, the y-intercept is where the line intersects the y-axis, or when x equals 0. x equals 0 when y equals 5, so the y-intercept is 5.

I hope this helps!

3 0

3 years ago

Read 2 more answers

Please can someone help?

alexandr402 [8]

Hey there! :)

Answer:

(5, -2), or x = 5 and y = -2.

Step-by-step explanation:

We can solve the two equations algebraically by eliminating a variable:

2x + 5y = 0

3x - 4y = 23

Eliminate the x variable by finding the least common multiple and multiplying both equations:

3(2x + 5y = 0)

2(3x - 4y = 23)

Distribute and subtract the bottom equation from the top:

6x + 15y = 0

6x - 8y = 46

------------------

0x + 23y = -46

23y = -46

y = -2.

Plug in y into an equation to solve for x:

2x + 5(-2) = 0

2x - 10 = 0

2x = 10

x = 5. Therefore:

The solution to this equation is (5, -2), or x = 5 and y = -2.

5 0

3 years ago

Read 2 more answers

Write an equation that has a graph with the shape of y = x^2, but shifted left 3 units.

svetoff [14.1K]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf % template detailing
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\$

$\bf \bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

now, with that template in mind, let's see

$\bf y=x^2\implies 
\begin{array}{llll}
y=(&1x&-0)^2\\
&B&C
\end{array}$

so, just change C to +3, thus C/B is 3/1

6 0

2 years ago