Answer:
1. The car is slowing down at a rate of 2.5mph/s
2. The greatest acceleration is 10 mph/s.
3. In the interval 4s to 16s the speed remains constant and has magnitude 25 mph.
Step-by-step explanation:
1. The deceleration of the car is from 16 seconds to 24 seconds is the slope
of the graph from 16 to 24:

the negative sign indicates that it is deceleration.
2. The automobile experiences the greatest change in speed when the slope is greatest because that is when acceleration/deceleration is greatest.
From the graph we see that the greatest slope of the graph is between 28 and 24 seconds. The acceleration the interval is the slope
:

3. The automobile experiences no acceleration in the interval 4 s to 16 s—that's the graph is flat.
The speed of the automobile in that interval, as we see from the graph, is 25 mph.
Answer:
y−3=2(x+3)
y=2x+9
that's the answer hope this helps u
Answer:
............................
Answer:
p^3 / q^12
Step-by-step explanation:
p^6 q^4
------------------
p^3 q^16
We know a^b / a^c = a^(b-c)
First with variable p
p^6 / p ^3 = p^(6-3) = p^3
Then with variable q
q^4 / q^16 = q^(4-16) = q^-12 and a^-b = 1/ a^b = 1 /q^12
p^3 * 1/ q^12
p^3 / q^12