Answer: Tristan can pick them out in 6 different ways
Step-by-step explanation: In the waiting room the four magazines all have an equal chance of being picked first and then others would be picked subsequently. If we are to pick magazine A first of all, then the others would be picked as B, C and D, or C, B and D, or D, B and C, and so on.
However, rather than spend so much time counting the different ways we can apply the mathematical method of permutation. Since choosing the first one means we can’t choose it again but others have to be chosen, and all four magazines each has an equal chance of being chosen first, then the number of all possible permutations is given as 4! (four factorial).
The question requires us to chose three out of the four magazines, so we shall apply 3!.
3! = 3 x 2 x 1
3! = 6
Therefore, there are 6 different ways to pick three out of the four magazines
<h3>Answer:</h3>
<h3>Explanation:</h3>
The rate shown in your graph is 3. (rise:run = 3:1) An equation with a lesser rate will have an x-coefficient that is less than 3. The x-coefficients in your answer choices appear to be ...
Of these values, only the first and last are less than 3.
Be careful for the moatman he’s tying right now
Answer: 3, 5, 7
Step-by-step explanation:
There is a "trick" to determine divisibility by 3: if the sum of the digits is divisible by 3, the number is divisible by 3.
3 + 1 + 5 = 9 which is a multiple of 3, so 315 is divisible by 3.
It works for 9 also. since the sum of the digits is 9, 315 is divisible by 9.
Divisibility by 5: any number that has the units digit 5 or 0 is divisible by 5.
For 7, I just tried it 315÷7= 45
Only even numbers are divisible by 2.
If a 3-digit number is divisible by 11, the middle digit will be the sum of the first and last digits. (That is not the case for 315) But 385 is divisible by 11, also 495, 253, and many others you can try for fun.
