Given the functions m(x) = 4x − 11 and n(x) = x − 10, solve m[n(x)]

1 answer:

5 0

M[n(x)] = m(x-10) = 4(x-10) -11 = 4x - 40 - 11 = 4x - 51

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$\huge \boxed{ \red{ \boxed{c)78 \: units ^{2} }}}$

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>

<h3>tips and formulas:</h3>

<h3>let's solve:</h3>

$\sf sustitute \: the \: value \: of \: \theta \: and \: r : \\ A_{shaded} = \frac{140}{360} \times \pi \times {8}^{2}$
$\sf simpify \: squre : \\ A_{shaded} = \frac{140}{360} \times \pi \times 64$
$\sf simpify \: fraction: \\ A_{shaded} = \frac{7}{18} \times \pi \times 64$
$\sf reduce \: 64: \\ A_{shaded} = \frac{7}{ \cancel{ \: 18} \: ^{9} } \times \pi \times \cancel{ 64} \: ^{32} \\ A_{shaded} = \frac{7}{9} \times \pi \times 32\\ A_{shaded} = \frac{224\pi}{9}$