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Pani-rosa [81]
2 years ago
15

Point S has the coordinates (6,-4).​

Mathematics
1 answer:
BabaBlast [244]2 years ago
7 0
Point S (6,-4)

Point T

(6 x -1, -4) = (-6, -4)

Point T = (-6,-4)

Point T shows the reflection of Point S across the y axis.

Hope this helps :)
P.S please give me brainlest
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Answer:

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Margarita [4]

Answer: 2sin^2x+sin2x+cos2x=0 ..... (1).

By using the trigonometric identities below :

sin2x=2sinxcosx

cos2x=cos^2x-sin^2x

We substitute the trigonometric identities into (1).

2sin^2x+2sinxcosx+cos^2x-sin^2x=0

By combining like terms .

sin^2x+2sinxcosx+cos^2x=0.....(2)

The equation (2) is equivalent to the following expression (3).

(sinx+cosx)(sinx+cosx)=0 .....(3).

sinx+cosx=0

cosx=-sinx

divide both sides by cosx

1=-sinx/cosx

-1=sinx/cosx

sinx/cosx=tanx

substitute

-1=tanx

tanx=-1

tangent is negative in 2nd and 4th quadrants

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tan315º=-1 (second answer)

Step-by-step explanation:

Please refer to the trigonometric identities used and explained above .

5 0
3 years ago
.In the coordinate x,y the point x is calledorigin<br>abscissa<br>line<br>y-axis<br>​
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<u>Answer:</u>

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In a Cartesian plane, we learn many such terms which represent a point, or a line, or cooridnates of some points etc.

Such terms are:

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5 0
2 years ago
What is this graphs slope?
Ksivusya [100]

Answer:

slope = -4

Step-by-step explanation:

Given the following points on the graph: (-1, 4) (1, -4)

Let (x1, y1) = (-1, 4)

(x2, y2) =  (1, -4)

Use the following slope formula:

m = \frac{y2 - y1}{x2 - x1}

m = \frac{-4 - 4}{1 - (-1)} = \frac{-8}{1 + 1} = \frac{-8}{2} = -4

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2 years ago
What is x, the distance between points A and A'? 2. 4 units 4. 8 units 13. 6 units 14. 4 units.
adelina 88 [10]

The distance between points A (3, -5) and A' (2, -3) is 2.4 units.

Given that,

The points A (3, -5) and A' (2, -3).

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According  to the question,

The distance between two points is determined by using the distance formula.

\rm Distance \ formula = \sqrt{(x_2-x_2) ^2+ (y_2-y_2)^2

Then,

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\rm Distance  = \sqrt{(2-3) ^2+ ((-3)-(-5))^2}\\\\ Distance  = \sqrt{(-1) ^2+ (2)^2}\\\\ Distance  = \sqrt{1+4}\\\\Distance = \sqrt{5}\\\\Distance = 2.4 \ units

Hence, The distance between points A (3, -5) and A' (2, -3) is 2.4 units.

For more details refer to the link given below.

brainly.com/question/8069952

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