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Scrat [10]
3 years ago
11

Companies that develop software for sale are called software ____.

Computers and Technology
1 answer:
yanalaym [24]3 years ago
4 0
Hello <span>Loveworld4058 
</span><span>
Answer: Companies that develop software for sale are called software vendors.


Hope This Helps
-Chris</span>
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Write a program that reads a list of integers, and outputs whether the list contains all even numbers, odd numbers, or neither.
Volgvan

Question:

Write a program that reads a list of integers, and outputs whether the list contains all even numbers, odd numbers, or neither. The input begins with an integer indicating the number of integers that follow. Assume that the list will always contain less than 20 integers.

Answer:

Written in Python

listlent = int(input("Length of List: "))

mylist = []

mylist.append(listlent)

for i in range(listlent):

    num = int(input(": "))

    mylist.append(num)

<em>    </em>

evens = 0

odds = 0

for i in range(1,listlent+1):

    if mylist[i]%2==0:

         evens=evens+1

    else:

         odds=odds+1

       

if(evens == 0 and odds != 0):

    print("All Odds")

elif(evens != 0 and odds == 0):

    print("All Even")

else:

    print("Neither")

Explanation:

This prompts user for length of the list

listlent = int(input("Length of List: "))

This initializes an empty list

mylist = []

The following iteration reads the list items from the user

<em>mylist.append(listlent)</em>

<em>for i in range(listlent):</em>

<em>     num = int(input(": "))</em>

<em>     mylist.append(num)</em>

   

The next two lines initialize even and odd to 0, respectively

<em>evens = 0</em>

<em>odds = 0</em>

<em />

The following iteration if a list item is even or odd

<em>for i in range(1,listlent+1):</em>

<em>     if mylist[i]%2==0:</em>

<em>          evens=evens+1</em>

<em>     else:</em>

<em>          odds=odds+1</em>

This checks and prints if all list items is odd        

<em>if(evens == 0 and odds != 0):</em>

<em>     print("All Odds")</em>

This checks and prints if all list items is even        

<em>elif(evens != 0 and odds == 0):</em>

<em>     print("All Even")</em>

This checks and prints if all list items is neither even nor odd

<em>else:</em>

<em>     print("Neither")</em>

4 0
2 years ago
Im drinking coffee. and working on school and watching a show. Whos with me?
Keith_Richards [23]

Answer:

me, americano and treasure box

Explanation:

4 0
3 years ago
The extent to which a program satisfies its specificationand fulfills the customer’s mission objectives is said to beachieving t
GuDViN [60]

Answer:

b) Reliability.

Explanation:

When the program gives correct output and fulfills the customer's requirements it is said to be reliable and said to be achieving reliability.

Correctness is when the program only provides correct solution.

Efficiency is when the program does the work in less time.

Usability means that the program is usable or not.

5 0
3 years ago
Directions. Read and analyze the sentences below. There are words or phrases to be corrected. Rewrite it on the blank accrording
devlian [24]

Full question attached

Answer and Explanation:

1. There’s need to ask for help and advice from people who have the

knowledge and skills in making a simple electrical gadget.

2. Adapter is used to plug appliances that are far from the main power source.

3. Do not touch the metal pipes while you are doing electrical repairs.

4. Shut off the power at the main switch or circuit breaker and unplug the equipment when working on electricity.

5. Pliers are tools used to grip, pull or cut electric wires.

From the above, we have corrected some of the errors that could be made in everyday home appliances or home electricity. In number 4, it is also worthy of note that shutting off power at the main switch will only require emergency situations otherwise we need only shut off the one for the problem circuit and leave the rest.

5 0
3 years ago
One of your start-ups uses error-correcting codes, which can recover the original message as long as at least 1000 packets are r
Marina CMI [18]

Answer:

Number of packets ≈ 5339

Explanation:

let

X = no of packets that is not erased.

P ( each packet getting erased ) = 0.8

P ( each packet not getting erased ) = 0.2

P ( X ≥ 1000 ) = 0.99

E(x) = n * 0.2

var ( x ) = n * 0.2 * 0.8

∴ Z = X - ( n * 0.2 ) / \sqrt{n*0.2*0.8}   ~ N ( 0.1 )

attached below is the remaining part of the solution

note : For the value of <em>n</em> take the positive number

5 0
3 years ago
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