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Leno4ka [110]
3 years ago
15

78-[5+3 of (25-20)] can you please help me solve this?​

Mathematics
2 answers:
Studentka2010 [4]3 years ago
4 0

Answer:

38

Step-by-step explanation:

➜78-[5+3×(25-20)]

➜78-[8(5)]

➜78-40

➜38

BabaBlast [244]3 years ago
4 0
78-(5 + 3 of (25-20)
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A TV studio has brought in 8 boy kittens and 10 girl kittens for a cat food commercial.
kondor19780726 [428]

Answer:

0.323 = 32.3% probability that the director chooses 3 boy kittens and 5 girl kittens.

Step-by-step explanation:

The kittens are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

A TV studio has brought in 8 boy kittens and 10 girl kittens for a cat food commercial.

This means that N = 8 + 10 = 18

We want 3 boys, so k = 8

The director is going to choose 8 of these kittens at random to be in the commercial.

This means that n = 8

What is the probability that the director chooses 3 boy kittens and 5 girl kittens?

This is P(X = 3).

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 3) = h(3,18,8,8) = \frac{C_{8,3}*C_{10,5}}{C_{18,8}} = 0.323

0.323 = 32.3% probability that the director chooses 3 boy kittens and 5 girl kittens.

3 0
3 years ago
there 7 adult adult chaperones and two third of the participants rode a large bus but if 54 people rode a large bus how students
statuscvo [17]

Hey!

Hope this helps...

~~~~~~~~~~~~~~~~~~~~~~~

54 * (2/3) = 36 students were on the bus.

54 - 36 = 18 chaperones were on the bus.

3 0
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kobusy [5.1K]

ok

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