Write the number below in expanded notation 75,966

GarryVolchara [31]

The last graph is the answer.

For the domain, the starting point is 0, and you can see a line that goes on forever towards the right, which would be your infinity. Its the same way with the range. Your starting point is the 0, and you can see that your line is pointed slightly upwards, which would still represent infinity.

4 0

3 years ago

Branlet will be marked so help out all my gemstones

Jobisdone [24]

Answer:

B is the right answer.

Step-by-step explanation:

56 + 0.08x = 164

0.08x = 164 - 56

0.08x = 108

0.08x/0.08 = 108/0.08

x = 1,350

To confirm that:

56 + 0.08x

56 + 0.08(1,350)

56 + 108

= 164

164 is the answer.

6 0

3 years ago

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During summer vacation, you charge people 8$ per hour for swimming lessons and 20$ registration fee. If you make 52$ one day, ho

zepelin [54]

Answer:

You taught for 4 hours

Step-by-step explanation:

Let this number of hours be x. Then:

Total earned = $20 + ($8/hr)x

Equate this to $52 and then solve the resulting equation for x:

20 + 8x = 52

Then 8x = 32, and x = 4. You taught for 4 hours.

3 0

3 years ago

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Determine and prove what shape is formed for the given coordinates for ABCD, and then find the

ella [17]

Answer:

Square

Step-by-step explanation:

Plot points A (10,-4), B (6,-7), C (3,-3), D (7,0) on the coordinate plane.

Find slopes of the sides:

$AB:\ \dfrac{-7-(-4)}{6-10}=\dfrac{3}{4}\\ \\BC:\ \dfrac{-3-(-7)}{3-6}=-\dfrac{4}{3}\\ \\CD:\ \dfrac{0-(-3)}{7-3}=\dfrac{3}{4}\\ \\DA:\ \dfrac{-4-0}{10-7}=-\dfrac{4}{3}$

The slopes of opposite sides are the same, so opposite sides are parallel. The slopes of adjacent sides have product of -1, then adjacent sides are perpendicular.

Find the lengths of all sides:

$AB=\sqrt{(10-6)^2+(-4-(-7))^2}=\sqrt{4^2+3^2}=\sqrt{16+9}=\sqrt{25}=5\ units\\ \\BC=\sqrt{(6-3)^2+(-7-(-3))^2}=\sqrt{3^2+4^2}=\sqrt{16+9}=\sqrt{25}=5\ units\\ \\CD=\sqrt{(3-7)^2+(-3-0)^2}=\sqrt{4^2+3^2}=\sqrt{16+9}=\sqrt{25}=5\ units\\ \\AD=\sqrt{(10-7)^2+(-4-0)^2}=\sqrt{3^2+4^2}=\sqrt{16+9}=\sqrt{25}=5\ units\\ \\$

All four sides are of the same length.

Quadrilateral ABCD is a square (all sides of equal length and perpendicular)

4 0

3 years ago

3(x + y) = 12

Mila [183]

Answer:

$\large\boxed{B)\ -2}$

Step-by-step explanation:

$\left\{\begin{array}{ccc}3(x+y)=12&(1)\\\\\dfrac{x}{2}=3&(2)\end{array}\right\\\\(2)\ \dfrac{x}{2}=3\qquad\text{multiply both sides by 2}\\\\2\!\!\!\!\diagup^1\cdot\dfrac{x}{2\!\!\!\!\diagup_1}=(2)(3)\\\\x=6\\\\\text{Put it to (1):}\\\\3(6+y)=12\qquad\text{divide both sides by 3}\\\\\dfrac{3\!\!\!\!\diagup^1(6+y)}{3\!\!\!\!\diagup_1}=\dfrac{12}{3}\\\\6+y=4\qquad\text{subtract 6 from both sides}\\\\6-6+y=4-6\\\\y=-2$

4 0

3 years ago

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