We are given with the expression y<span> = b cos t + t2 sin t and is asked to differentiate the function in terms of t. Based in the power law and law of products, we apply these to the given expresssion. the derivative is y' = -b sin t + t^2 * (cos t) + sin t * 2t. This is equal to </span>y' = sin t (-b +2t) + t^2 cos t.
<h3>
Answer: 15</h3>
===============================================
Work Shown:
d = common difference
p = first term = 24
q = second term = a+d = 24+d
r = third term = q+d = 24+d+d = 24+2d = 6
------------
Solve for d
24+2d = 6
2d = 6-24
2d = -18
d = -18/2
d = -9
We add -9 to each term to get the next term. This is the same as subtracting 9 from each term to get the next term.
------------
First term = 24
Second term = 24-9 = 15
Third term = 15-9 = 6
We get the sequence 24, 15, 6
Answer:
Yes
Step-by-step explanation:
I think it is proportional relationship. I hope my answer help you.
Answer:
3^9x=3^-2x
Step-by-step explanation:
27^3x=(1/9)^x
3^3×3x=(1/3^2)^x
3^9x=3^-2x