Answer:
Step-by-step explanation:
Let the number of dimes be d and quarters be q
<u>The value is $8.80 = 880¢, so:</u>
- 10d + 25q = 880 ⇒ 2d + 5q = 176
<u>If the dimes were quarters and the quarters were dimes, the coins' total value would be $7.30 or 730¢</u>
- 25d + 10q = 730 ⇒ 5d + 2q = 146
<u>Now we have 2 equations. Solving the system by elimination, subtract 5 times the second equation from twice the first equation:</u>
- 2(2d + 5q) - 5(5d + 2q) = 2(176) - 5(146)
- 4d - 25d = -378
- -21d = -378
- d = -378/-21
- d = 18
In probability, you study the chances, odds or likelihood of the event occurring. This is determined by dividing the number of possibilities to the total number of events. But terms may come up such as 'mutually exclusive'. Suppose, event A is for students ages 5-10, while event B is for students ages 11-15. The events A and B are said to be mutually exclusive when they do not intersect or meet at some point. In other words, when a student is in group A, he cannot be in group B because that becomes invalid and untrue. That seems logical because a student cannot be both 6 years old and 12 years old, right?
Hence, the answer to this question is letter C.
<span>Well divide
<span> 2 x 10^-4 and 1 x 10^-5 </span>to get 2 x 10^1</span>
Lets say Y is the amount they will save.
So Melinda's savings could be described by the equation Y=22+10X, where X is the number of weeks. The same goes to George, but his equation would be Y=10+13X.
To save the same amount, their equations must match:
22+10X = 10+13X
Solving this, one gets
12 = 3x
=> 4=x
So the answer is 4 weeks.
I hope this helps you
p^0=1
m^-8=1/m^8
m^-8.p^0= 1/m^8
