Answer:
it is already in the simplest form
Step-by-step explanation:
23 is prime
<u>Answer:</u>
The basic identity used is
.
<u>Solution:
</u>
In this problem some of the basic trigonometric identities are used to prove the given expression.
Let’s first take the LHS:

Step one:
The sum of squares of Sine and Cosine is 1 which is:

On substituting the above identity in the given expression, we get,
Step two:
The reciprocal of cosine is secant which is:

On substituting the above identity in equation (1), we get,

Thus, RHS is obtained.
Using the identity
, the given expression is verified.
The domain is how far the graph stretches horizontally (on the x-axis).
Domain: ( -∞ , ∞ ) or -∞ < x < ∞
The range is how long the graph stretched vertically (on the y-axis).
Range: ( -∞ , 2 ] or -∞ < y ≤ 2
The zeros are where the graph intersects with the x-axis. In other words, the x-values when y=0.
Zeros: x = -1 and x = 3
Answer:
0.86
Step-by-step explanation:
Draw the triangle.
Since ∠J=90°, this is a right triangle, so we can use SOH-CAH-TOA to find sin∠I.
sin∠I = 56/65
sin∠I = 0.86
Answer:
This is a geometric sequence because any term divided by the previous term is a constant called the common ratio. r=36/18=18/9=2 A geometric sequence is expressed as
\begin{gathered}a_n=ar^{n-1},\text{ where a=initial term, r=common ratio, n=term number}\\ \\ a_n=9(2^{n-1})\\ \\ a_6=9(2^5)\\ \\ a_6=288\end{gathered}an=arn−1, where a=initial term, r=common ratio, n=term numberan=9(2n−1)a6=9(25)a6=288