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2 years ago

I need help pls i have to be done by 2

Mathematics

1 answer:

andreev551 [17]2 years ago

6 0

Answer:

ASA postulate: 1 side, 2 angles equal

Step-by-step explanation:

ASA postulate: 1 side, 2 angles equal

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4/12 of a cake was left over if another 3/12 of the cake is eaten

inn [45]

There would be 1/12 of the cake left.

3 0

2 years ago

Craig scored 12 points in a game. Marla scored twice as many points as Craig but 5 fewer than Nelson scored. Write an expression

asambeis [7]

First write what are given from the question
We write "Craig scored 12 points in a game" as
⇒ c = 12 (first equation)
We write "Marla scored twice as many points as Craig but 5 fewer than Nelson scored" as
⇒ m = 2c (second equation)
⇒ m = n - 5 (third equation)

Second, find the expression for n based on what we write above
From the second and third equation
⇒ m = m
⇒ n - 5 = 2c
Subtitute from the first equation
⇒ n - 5 = 2c
⇒ n - 5 = 2(12)
⇒ n - 5 = 24

This is the expression to find how many nelson scored
n - 5 = 24

4 0

2 years ago

Geo help pls! 20 PTS

Mice21 [21]

2 is 160, 3 is 10 so it’ll add to 180

3 0

2 years ago

I need help on this question about percentages

Vera_Pavlovna [14]

Sales above monthly quota = 23800 - 17000 = $6800

So her commission = 0.05 * 6,800 = $340

Therefore her total salary for the month = 3600 + 340

= $3,940 (answer).

7 0

3 years ago

Read 2 more answers

Mr. Harris is packaging items to give to his students. He has 48 pencils and 30 notebooks. He wants each package to contain the

guapka [62]

Answer:

The maximum number of packages that can be made with each package have same number of each item is = 6

Step-by-step explanation:

Given:

Mr. Harris has 48 pencils and 30 notebooks.

To find the number of packages he can make with each package have same number of each item.

Solution:

Number of pencils = 48

Number of notebooks = 30

In order to find the number of packages he can make with each package have same number of each item, we will find the greatest common factor of the given numbers.

To find the G.C.F., we will list down the prime factors of each.

$48=2\times 2\times 2\times 2\times 3$

$30=2\times 3\times 5$

We find that the G.C.F. = $2\times 3$ = 6

Thus, the maximum number of packages that can be made with each package have same number of each item is = 6

4 0

2 years ago