Answer:
Choice A. (10, -1)
Choice B. (-8, 9)
Choice D. (6, -3)
Step-by-step explanation:
If we plug the coordinates of point A into the inequality, then we get,
x+y > -2
10 + (-1) > -2
9 > -2
That last inequality is a true statement since 9 is to the right of -2 on the number line. That means (10,-1) is a solution. Choice A is one of the answers.
Choices B and D are also answers for similar reasons.
Something like choice C is not a solution because
x+y > -2
-1+(-9) > -2
-10 > -2
Which is false.
You should find that choice E is false as well.
If you graphed the inequality and all of the points mentioned (see below), then you can visually confirm the answers. Notice how points A, B and D are in the blue shaded region which is the solution set.
The point E on the boundary does not count as a solution. This is due to the lack of "or equal to" portion of the inequality sign. That visually shows point E is not a solution. Point C isn't a solution either as it's nowhere near the blue shaded region.
Answer:
10
Step-by-step explanation:
Subtract -4 from 6
6 - -4
Subtracting a negative is like adding
6 +4
10
Answer:
6x+y=36
Step-by-step explanation:
6x - A rose is $6 and you do not know how many she will buy so you would put an "x" after that symbolizing how many she will buy.
y - Carnations cost $1 and the amount purchased is unknown so you would use "y". Because they cost 1 dollar, you will not need to add 1 in front of "y" because "y" by itself is already known as one variable.
36 - The total cost of the arrangement is ultimately going to be $36
Answer:
The slope of line A equals one-half. The slope of line B equals 2.
Step-by-step explanation:
The equation of Line A is given by : 
........... (1)
The equation of Line B is given by : y = 2x - 3 ............. (2)
Those two equations are in slope-intercept form i.e. y = mx + c, where m is the slope of the line.
Now, the slope of line A equals one-half. The slope of line B equals 2.
Therefore, option 1 will be correct. (Answer)
Answer:sdaf f a
Step-by-step explanation:edsaf dsf
