Answer:
-4
Step-by-step explanation:
There are many methods to solve this system of equations.
I will use the elimination method.
First step:
Multiply the first equation by -2
2(2x-3y) = -14(-2)
-4x + 6y = 28
Multiply the second equation by 3 so you can eliminate the y term
3(3x-2y) = -6(3)
9x-6y = -18
Second step: Add the equations vertically(Basically adding like terms)
-4x+6y = 28
+
9x - 6y = -18
5x = 10
Third step: Solve for x
x = 2
Substitute the x-value into any of the original equation to get the y value
3(x) - 2y = -6
3(2) - 2y = -6
6 - 2y = -6 (Since we are solving for y, it will be isolated and we will move 6 to the other side)
-2y = -6 - 6(Moving 6 to the other side makes it negative)
Solve for y by dividing by -2
y = 6
So (x, y) = (2, 6)
Since the question is asking to subtract x and y
2-6 = -4
Answer:
??
Step-by-step explanation:
pls type the question properly have a good day:-)
Answer:
5.209 or A
Step-by-step explanation
5^x-4=7
reserve 4
log sides
x-4 log5 and log7
x-4=log7/log5
+4 or number of your equation
x=log5/log7 +4
use calculator
get answer
5.209
EDIT: Got a 100 on the test this is correct
The number in the blank box should be 44 because it said that "3 times x and 4 times y is 44".
You need to multiply the first equation by 3:
3x + 3y = 39.
Then, subtract the first equation from the second equation:
3x - 3x = 0
4y - 3y = y
44 - 39 = 5
Your new equation should look like this: y = 5
Now, substitute y = 5 into the first original equation:
x + 5 = 13
x = 8
Ans. (x, y) = (8, 5)
Out of 3 coins, if you are given that 1 is on tails, then the most heads you could have is 3 coins - 1 tails = 2 heads.
The probability of getting 3 heads would be 0.
