If he goes there 4 times a week then $8 plus $2 equals $10 and times $10 by 4 times a week equals $40
So Elijah spends $40 a week at the restaurant
Answer:
Therefore 200.96 ft.of fencing are needed to go around the pool path.
Step-by-step explanation:
Given, a circular swimming pool has a radius of 28ft. There is a path all the way around the pool. The width of the path 4 ft.
The radius of the outside edge the pool path is
= Radius of the pool + The width of the path
= (28+4) ft
= 32 ft.
To find the length of fencing, we need to find the circumference of outside the pool path.
Here r= 32 ft
The circumference of outside edge of the pool path
=
![=(2\times 3.14 \times 32) ft](https://tex.z-dn.net/?f=%3D%282%5Ctimes%203.14%20%5Ctimes%2032%29%20ft)
=200.96 ft.
Therefore 200.96 ft.of fencing are needed to go around the pool path.
Answer:
What will help is labeling the diagram with the given info..A proof always ends with the statement you have to prove.
Step-by-step explanation:
STATEMENT..............REASON
1) ∠F≅∠C 1) Given
2) E is the midpoint of GD 2) Given
3) GE≅ED 3) If a point is a midpoint then 2 ≅ segments are formed
4) FE≅EC 4) Same as 3
5)∠G≅∠D 5)
6) FG≅CD 6)
I tried my best with step 5 and 6..but you know step 6 has to be the prove statement but i don't know what the reason would be. I hope i helped a bit though.
Answer:
Rounded to nearest tenths = 0.2