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3 years ago

,8. If A= {x:x is a factor of 72}

Mathematics

1 answer:

tatuchka [14]3 years ago

4 0

Answer:

No element is common to all the sets

AnBnc = { }

Step-by-step explanation:

If A= {x: xis a factor of 72}

A = {2, 3, 4, 6, 8, 9, 12, 18, 36, 72}

If B= {x: 72x+3<2x-3).

72x+3 <2x-3

72x - 2x < -3-3

70x < -6

x < -6/70

x < -3/35

x< -0.0857

C= {x:x<20}

C = {-∞, 19}

The intersection of the sets AnBnc = {} i.e an empty set

Note that intersection means all the elements common to the three sets

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14 Type the correct answer in each box. Use numerals instead of words. a Ava, Lucas, and Maria are playing a game where they pas

jeka94

Answer:

Maria–Ava: 15.7 feet
Lucas–Maria: 10.1 feet
angle at Maria: 50°

Step-by-step explanation:

The cosine and tangent functions are useful here. The relevant relations are ...

Cos = Adjacent/Hypotenuse

Tan = Opposite/Adjacent

The distance from Maria to Ava (ma) is the hypotenuse of the triangle, so we have ...

cos(40°) = 12/ma

ma = 12/cos(40°) ≈ 12/0.76604 ≈ 15.7 . . . feet

The distance from Lucas to Maria (ml) is the side opposite the given angle, so we have ...

tan(40°) = ml/12

ml = 12·tan(40°) ≈ 12·0.83910 ≈ 10.1 . . . feet

The angle formed at Maria's position is the complement of the other acute angle in the right triangle:

M = 90° -40° = 50°

In summary, ...

Maria–Ava: 15.7 feet
Lucas–Maria: 10.1 feet
angle at Maria: 50°

5 0

3 years ago

164+56-[3+4+1]=<br><br> WHAT IS THE ANSWER SHOW THE WORK

Law Incorporation [45]

164+56−(3+4+1) =220−(3+4+1) =220−(7+1) =220−8 =212

7 0

3 years ago

Read 2 more answers

1. The mechanics at Lincoln Automotive are reborning a 6 in deep cylinder to fit a new piston. The machine they are using increa

Firdavs [7]

Answer:

$0.0239\frac{in^{3}}{min}$

Step-by-step explanation:

In order to solve this problem, we must start by drawing a diagram of the cylinder. (See attached picture)

This diagram will help us visualize the problem better.

So we start by determining what data we already know:

Height=6in

Diameter=3.8in

Radius = 1.9 in (because the radius is half the length of the diameter)

The problem also states that the radius will increase on thousandth of an inch every 3 minutes. We can find the velocity at which the radius is increasing with this data:

$r'=\frac{1/1000in}{3min}$

which yields:

$r'=\frac{1}{3000}\frac{in}{min}$

with this information we can start solving the problem.

First, the problem wants us to know how fast the volume is increasing, so in order to find that we need to start with the volume formula for a cylinder, which is:

$V=\pi r^{2}h$

where V is the volumen, r is the radius, h is the height and π is a mathematical constant equal approximately to 3.1416.

Now, the height of the cylinder will not change at any time during the reborning, so we can directly substitute the provided height, so we get:

$V=\pi r^{2}(6)$

$V=6 \pi r^{2}$

We can now take the derivative to this formula so we get:

$\frac{dV}{dt}=2(6)\pi r \frac{dr}{dt}$

Which simplifies to:

$\frac{dV}{dt}=12\pi r \frac{dr}{dt}$

We can now substitute the data provided by the problem to get:

$\frac{dV}{dt}=12\pi (1.9) (\frac{1}{3000})$

which yields:

$\frac{dV}{dt}=0.0239\frac{in^{3}}{min}$

3 0

4 years ago

How many seconds will light leaving Los Angeles take to reach the following locations (a) San Francisco (about 500km), (b) Londo

kondor19780726 [428]

Answer:

a) It takes 0.0017s for the light to reach San Francisco.

b) It takes 0.033s for the light to reach London.

c) It takes 1.334s for the light to reach Mars.

d) It takes 149.7s for the light to reach Venus.

Step-by-step explanation:

Here we can solve this problem by using this following formula:

$s = \frac{d}{t}$

In which s is the speed(in km/s), d is the distance(in km) and t is the time(in s).

The light speed is 299 792 458 m / s = 299,792.458 km/s, so $s = 299,792.458$

(a) San Francisco (about 500km)

Find t when $d = 500$ . So

$s = \frac{d}{t}$

$299,792.458 = \frac{500}{t}$

$299,792.458t = 500$

$t = \frac{500}{299,792.458}$

$t = 0.0017s$

It takes 0.0017s for the light to reach San Francisco.

b) London(about 10,000km)

Find t when $d = 10,000$ . So

$s = \frac{d}{t}$

$299,792.458 = \frac{10,000}{t}$

$299,792.458t = 10,000$

$t = \frac{10,000}{299,792.458}$

$t = 0.033s$

It takes 0.033s for the light to reach London.

(c) the Moon (400,000km)

Find t when $d = 400,000$ . So

$s = \frac{d}{t}$

$299,792.458 = \frac{400,000}{t}$

$299,792.458t = 400,000$

$t = \frac{400,000}{299,792.458}$

$t = 1.334s$

It takes 1.334s for the light to reach Mars.

(d) Venus (0.3 A.U. from Earth at its closest approach).

Each A.U. has 149,59,7871 km.

So 0.3 A.U. = 0.3*(149,597,871) = 44,879,361.3. This means that $d = 44,879,361.3$ . So:

$s = \frac{d}{t}$

$299,792.458 = \frac{44,879,361.3}{t}$

$299,792.458t = 44,879,361.3$

$t = \frac{44,879,361.3}{299,792.458}$

$t = 149.7s$

It takes 149.7s for the light to reach Venus.

3 0

3 years ago

Please help with this question.

Rzqust [24]

(cos Ф -cos Ф)² + (cos Ф + cos Ф)²

Firstly: (cos Ф -cos Ф)² = 0² = 0

Secondly :(cos Ф + cos Ф)² = (2cos Ф)². = 4. (cos Ф)² = 4cos² Ф

Mind you when you raise a cosine (or sin or tan...) to the n power, the n power should affect the cosine only and NOT the angle Ф

4 0

3 years ago