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Alisiya [41]
3 years ago
7

X2+y2-4+2y-11=0 what are the center and radius of the circle?

Mathematics
1 answer:
andriy [413]3 years ago
8 0
<span>x^2 + y^2 - 4x + 2y - 11 = 0

You need to complete the square for both x and y.

x^2 - 4x + y^2 + 2y = 11
</span>
x^2 - 4x + 4 + y^2 + 2y + 1 = 11 + 4 + 1

(x - 2)^2 + (y + 1)^2 = 16

(x - 2)^2 + (y + 1)^2 = 4^2

The center is (2, -1).
The radius is 4.
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Which linear inequality is represented by the graph?
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Where is the graph?
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3 years ago
Which expression represents the distance between the points (11, 4) and (5,8)?
antiseptic1488 [7]

Answer:

\displaystyle d = 2\sqrt{13}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)

<u>Algebra II</u>

  • Distance Formula: \displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

Point (11, 4) → x₁ = 11, y₁ = 4

Point (5, 8) → x₂ = 5, y₂ = 8

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

  1. Substitute in points [Distance Formula]:                                                       \displaystyle d = \sqrt{(5-11)^2+(8-4)^2}
  2. [√Radical] (Parenthesis) Subtract:                                                                 \displaystyle d = \sqrt{(-6)^2+(4)^2}
  3. [√Radical] Evaluate exponents:                                                                    \displaystyle d = \sqrt{36+16}
  4. [√Radical] Add:                                                                                               \displaystyle d = \sqrt{52}
  5. [√Radical] Simplify:                                                                                         \displaystyle d = 2\sqrt{13}
4 0
3 years ago
What is the equation of the line that passes through the origin and is perpendicular to the line 4x+3y=6
frez [133]

The Equation of a Line

The slope-intercept form of a line can be written as:

y = mx + b

Where m is the slope of the graph of the line and b is the y-intercept.

In the specific case where the line passes through the origin (0,0), we can find the value of b by substituting x=0 and y=0:

0 = m(0) + b

Solving for b:

b = 0.

Thus, the equation of the line reduces to:

y = mx

We only need to find the value of the slope.

That is where we need the second data. Our line is perpendicular to the line of equation 4x + 3y = 6.

Solving for y:

y=-\frac{4}{3}x+2

The slope of the second line is -4/3.

We must recall that if two lines of slopes m1 and m2 are perpendicular, then:

m_1\cdot m_2=-1

Substituting the value of m1 and solving for m2:

\begin{gathered} -\frac{4}{3}\cdot m_2=-1 \\ m_2=\frac{3}{4} \end{gathered}

The slope of our line is 3/4 and the required equation is:

y=\frac{3}{4}x

From this last equation, we need to find the general form of the line.

Multiply both sides of the equation by 4:

4y = 3x

Subtract 3x on both sides:

4y - 3x = 0

Reorder:

-3x + 4y = 0

5 0
1 year ago
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