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OLEGan [10]
3 years ago
11

Help!!! Please help me I need help on my homework!​

Mathematics
2 answers:
vekshin13 years ago
4 0

Answer:

82 is the answer to the question

Reptile [31]3 years ago
3 0

Answer:

82

Step-by-step explanation:

It's a simple question... since all of the other answers are above 84 and we can clearly see October's average is below that, the only logical answer is 82 I am pretty confident you got it right

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How do you rationalize the numerator in this problem?
maw [93]

To solve this problem, you have to know these two special factorizations:

x^3-y^3=(x-y)(x^2+xy+y^2)\\ x^3+y^3=(x+y)(x^2-xy+y^2)

Knowing these tells us that if we want to rationalize the numerator. we want to use the top equation to our advantage. Let:

\sqrt[3]{x+h}=x\\ \sqrt[3]{x}=y

That tells us that we have:

\frac{x-y}{h}

So, since we have one part of the special factorization, we need to multiply the top and the bottom by the other part, so:

\frac{x-y}{h}*\frac{x^2+xy+y^2}{x^2+xy+y^2}=\frac{x^3-y^3}{h*(x^2+xy+y^2)}

So, we have:

\frac{x+h-h}{h(\sqrt[3]{(x+h)^2}+\sqrt[3]{(x+h)(x)}+\sqrt[3]{x^2})}=\\ \frac{x}{\sqrt[3]{(x+h)^2}+\sqrt[3]{(x+h)(x)}+\sqrt[3]{x^2}}

That is our rational expression with a rationalized numerator.

Also, you could just mutiply by:

\frac{1}{\sqrt[3]{x_h}-\sqrt[3]{x}} \text{ to get}\\ \frac{1}{h\sqrt[3]{x+h}-h\sqrt[3]{h}}

Either way, our expression is rationalized.

7 0
4 years ago
Mario has 20 yards to mow this week by Wednesday he had mowed 50% of the yards how many yards had he mowed by Wednesday?
Fofino [41]
I am guessing 10 yards?
4 0
4 years ago
Read 2 more answers
3 − (2x − 5) < −4(x + 2)
Ede4ka [16]

Answer:

x < -8

Step-by-step explanation:

3 - (2x - 5) < -4(x + 2)

3 - 2x + 5 < -4*x -4*2

-2x + 8 < -4x - 8

-2x + 4x < -8 -8

2x < -16

x < -16/2

x < -8

7 0
4 years ago
Find the product: (-4x - 3y)( - 2x + y)<br>A. 8x2– 3y2<br>B. 8x2 + 10xy - 3y2<br>D. 8x2 2xy - 3y2​
bogdanovich [222]
D, 8x^2 + 2xy - 3y^2.
7 0
3 years ago
Divide and simplify (-11x^6 u^3 + 9x u^3) / (-3x^4 u^2)
Semenov [28]

Answer:

11ux^2/3-3u/x^3 factor the numerators and the denominators and cancel the common factor

Step-by-step explanation:


6 0
3 years ago
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