Answer:
tan 72° = h/30
h = 30 tan 72°
h = 92.33
The ladder reaches a height of 92.33 ft.
a. The 
component tells you the particle's height:
b. The particle's velocity is obtained by differentiating its position function:
so that its velocity at time 
is
c. The tangent to 
at is
The class is weighted as follows:
60% Regular Tests
10% Final Exam
15% Project
15% Homework
The total weighted points possible for the class are as follows:
(100+100+100+100+100)*.6 + 100*.1 + 100*.15 + 100*.15 = 340
To calculate her individual final weighted grade we plug in her scores for each category and complete the following computation:
(92+83+77+84+82)*.6 + 88*.1 + 95*.15 + 77*.15 = 285.4
So her weighted grade percent would be 285.4/340 = 83.9% which is a B.
Answer:
x^2 -7x-18
Step-by-step explanation:
(x-9)(x+2)
FOIL
first x*x = x^2
outer 2x
inner -9x
last -9*2 =-18
Add together
x^2 +2x-9x-18
Combine like terms
x^2 -7x-18
The ad cost for half page Saturday after discount is
15% of 380 = 0.15×380 = 57
380 - 57 = 323
The ad cost for half page Tuesday after discount is
15% of 330 = 0.15×330 = 49.5
330 - 49.5 = 280.5
Cost of the ads for 10 Saturdays and 10 Tuesdays
(10×323)+(10×280.5) = 3230+2805 = 6035
