f(x) = 1 - ²/ₓ₃
y = 1 - ²/ₓ₃
y = 1 - ²/ₓ₃
y - 1 = ⁻²/ₓ₃
x - 1 = -2/y³
y³(x - 1) = -2
y³ = ⁻²/ₓ₋₁
y = ∛⁻²/ₓ₋₁
y = -∛(2x² - 4x + 2)/x - 1
f⁻¹(x) = -∛(2x² - 4x + 2)/x - 1
Answer:
We have been given that a car can travel 476 miles on 14 gallons of gas and we are asked to write an equation relating the distance d to the number of gallons g.
We can set an equation as distance traveled is directly proportional to number of gallons used in travelling that distance.
Now we will find out K(number of miles traveled in one gallon of gas) by substituting our given values in this equation.
Therefore, we can see that car travels 34 miles in one gallon of gas.
Now we can use this information to find out how many gallons of gas does this car need to travel 578 miles.
Let us divide number of miles to be traveled by number of miles traveled in one gallon of gas to find out number of gallons of gas needed.
Therefore, car need 17 gallons of gas to travel 578 miles.
Step-by-step explanation:
Answer:
1.25 seconds
Step-by-step explanation:
Cosine is a maximum at cos(0) = 1, and a minimum at cos(π) = -1.
At the maximum:
8π/5 t = 0
t = 0
At the minimum:
8π/5 t = π
t = 5/8
t = 0.625
The time from maximum to minimum is 0.625 seconds. Therefore, the time from minimum back to maximum is also 0.625 seconds. So the total time is:
0.625 + 0.625 = 1.25
