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3 years ago

If sin∠X = cos∠Y and m∠X = 72°, what is the measure of ∠Y?

Mathematics

2 answers:

Nastasia [14]3 years ago

6 0

Answer:

The answer is 18.

Step-by-step explanation:

90-72=18

dezoksy [38]3 years ago

3 0

Answer:

A. 18°

Step-by-step explanation:

Using the cofunction identity

sin x = cos(90 - x)

Hence

sin72° = cos(90 - 72)° = cos18° ⇒ ∠Y = 18°

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Among all monthly bills from a certain credit card company, the mean amount billed was $465 and the standard deviation was $300.

Fynjy0 [20]

Answer:

0.02% probability that the average amount billed on the sample bills is greater than $500.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 465, \sigma = 300, n = 900, s = \frac{300}{\sqrt{900}} = 10$ .

What is the probability that the average amount billed on the sample bills is greater than $500?

This probability is 1 subtracted by the pvalue of Z when $X = 500$ . So

$Z = \frac{X - \mu}{s}$

$Z = \frac{500 - 465}{10}$

$Z = 3.5$

$Z = 3.5$ has a pvalue of 0.9998.

So there is a 1-0.9998 = 0.0002 = 0.02% probability that the average amount billed on the sample bills is greater than $500.

8 0

3 years ago

Pls pls pls pls help

artcher [175]

Answer:

see below

Step-by-step explanation:

A. Reflection across the y-axis replaces each x coordinate with its opposite.

B. Rotation 90° CW does the transformation (x, y) ⇒ (y, -x)

C. This is a translation left 2 units.

D. Rotation 90° CCW does the transformation (x, y) ⇒ (-y, x)

E. This is a translation left 7 and down 2.

In the attached graphs, we have identified a point that is a corresponding point on each figure. This is so you can see how the various transformations move it and the rest of the figure in relation to it. 90° arcs are shown so you can see the rotations more easily.

The figures are labeled and color coded in accordance with the problem statement.

8 0

3 years ago

Consider the graph of the expotential function y= 3(2)^x

victus00 [196]

Answer:

<h2>y-intercept = 3</h2><h2>x-intercept - not exist</h2><h2>the graph is increasing</h2>

Step-by-step explanation:

The exponential function:

$f(x)=b(a)^x$

has y-intercept for x = 0

hasn't x-intercept

if a > 1, then is increasing

if 0 < a < 1, then is decreasing

We have

$y=3(2)^x$

a = 2 >1 - increasing

for x = 0:

$y=3(2)^0=3(1)=3$

8 0

3 years ago

The graph of the even function F(X) Has 5 x-intercepts if (6,0) is the one of the intercepts what set of points can be the other

alex41 [277]

f(x) being even means

f(x) = f(-x)

So the zeros come in positive and negative pairs. If there are an odd number of intercepts like there are here, it's because one of them is x=0 which is its own negation.

Given zero x=6 we know x=-6 is also a zero.

So we know three zeros, and know the other two zeros are a positive and negative pair.

The only choice with (-6,0) and (0,0) is A.

Choice A

3 0

3 years ago

Read 2 more answers

PLEASE ANSWER ALL BIG REWARD

sleet_krkn [62]

Answer:

multiplying
similar figures
scale factor
(x, y) (–3x, –3y) and (x, y) (0.23x, 0.23y)
(x, y) --> (2x, 4y)
Need diagram
A. The line segment has become longer with endpoints D' (-12, -10) and E' (6 -8).
Need image
Reduction
Enlargement

<em>good luck, i hope this helps :)</em>

6 0

3 years ago