Answer:
The measure of the third arc is 
Step-by-step explanation:
step 1
we know that
The measurement of the external angle is the semi-difference of the arcs which comprises
in this problem
Let
x----> the greater arc of the circle intercepted by the secant and the tangent
y----> the smaller arc of the circle intercepted by the secant and the tangent
----> equation A
-----> equation B
Substitute equation B in equation A and solve for y
Find the value of x
step 2
Find the measure of the third arc
Let
z------> the measure of the third arc
we know that
-----> complete circle
substitute the values and solve for z
Answer:
x < 5
Step-by-step explanation:
2 x +8 < 18
Subtract 8 from each side
2x+8-8 < 18 -8
2x< 10
Divide by 2
2x/2 < 10/2
x < 5
= 12*5 + 12*3i - 5*2i - 6i^2 (remember that i^2 = -1) so:-
= 60 +26i - 6*(-1)
= 60 + 26i + 6
= 66 + 26i
Answer:
-1
Step-by-step explanation:
Based on the photo the asymptote will be x= - 1 because it is approaching it but never touching it
19. 4/6 or 2/3 (lowest term) or 2:3 in ratio
20. 2/3 or 2:3 in ratio
21. 5/12 or 5:12 in ratio
22. 14
To get geometric mean, multiply the numbers then get the square root of the product (if there are two numbers), cube root (if there are three numbers), and so on. In this case, 7*28 = 196; √196 = 14
23. 10 ft : 2.5 ft.
Convert the values so that it will be similar. In this case, 30 inches is converted to ft.
24. 24 is the Perimeter of ABCDE.
ABCDE and FGHJK are similar shapes. Similar shapes have proportional measurements.
Now compute for the sides of ABCDE.
AB = 4; BC = ?; CD = ?; DE = ?; EA = ?
AB + BC + CD + DE + EA
4 + 4 + 5 + 6 + 5 = 24
Find BC:
AB/BC = FG/GH
4/BC = 8/8
8BC = 32
BC = 4
Find CD:
BC/CD = GH/HJ
4/CD = 8/10
8CD = 40
CD = 5
Find DE:
CD/DE = HJ/JK
5/DE = 10/12
10DE = 60
DE = 6
Find EA
DE/EA = JK/KF
6/EA = 12/10
12EA = 60
EA = 5
