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Greeley [361]
3 years ago
15

How much is 5/9 of -3/5? A) 1/2 B) -1/3 C) 1/7 D) -25/27

Mathematics
2 answers:
slamgirl [31]3 years ago
6 0

Answer:

B) -1/3

Step-by-step explanation:

-3/5 * 5/9

= -0.33333 repeating or -1/3

irina1246 [14]3 years ago
5 0
The answer is A 1/2 sorry if I’m wrong if not A its c
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5x =2 writing your answer as a fraction in it’s simplest form
suter [353]

Answer:

x = 2/5

Step-by-step explanation:

5x=2

Divide  each side by 5

5x/5 = 2/5

x = 2/5

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3 years ago
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What value is added to both sides of the equation x2 − 6x = 10 in order to solve by completing the square?
oksano4ka [1.4K]
To find the perfect square needed, you take the "middle" value and half it, then square it. so in this case, take -6, half it into 3, and square it to get 9. you'll be adding 9 to both sides
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3 years ago
(1Q) Describe how to transform the graph of g(x) = lnx into the graph of f(x)= ln(x-4)+3?
xxMikexx [17]

Answer:

B

Step-by-step explanation:

The correct answer is to go 4 units right (the direction is opposite to the sign) and 3 units up. The up and down direction is the same number as after the function.

Red: Parent Function y = ln(x)

Blue: 4 units right. 3 units up.

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3 years ago
A farmer has a field in the shape of a triangle. The farmer has asked the manufacturing class at your school to build a metal fe
Finger [1]

Answer:

<em>Fencing required = 1586 m</em>

Step-by-step explanation:

The given statements can be thought of a triangle \triangle ABC as shown in the diagram attached.

A be the 1st vertex, B be the 2nd vertex and C be the 3rd vertex.

Distance between 1st and 2nd vertex, AB = 435 m

Distance between 2nd and 3rd vertex, AC = 656 m

\angle A =49^\circ

To find:

Fencing required for the triangular field.

Solution:

Here, we know two sides of a triangle and the angle between them.

To find the fencing or perimeter of the triangle, we need the third side.

Let us use <em>Cosine Rule </em>to find the third side.

Formula for cosine rule:

cos A = \dfrac{b^{2}+c^{2}-a^{2}}{2bc}

Where  

a is the side opposite to \angle A

b is the side opposite to \angle B

c is the side opposite to \angle C

\Rightarrow cos 49^\circ = \dfrac{656^{2}+435^{2}-BC^{2}}{2\times 435\times 656}\\\Rightarrow BC^2 = 430336+189225-2 (435)(656)cos49^\circ\\\Rightarrow BC^2 = 430336+189225-570720\times cos49^\circ\\\Rightarrow BC^2 =619561-570720\times cos49^\circ\\\Rightarrow BC \approx 495\ m

Perimeter of the triangle = Sum of three sides = AB + BC + AC

Perimeter of the triangle = 435 + 495 + 656 = <em>1586 m</em>

<em></em>

<em>Fencing required = 1586 m</em>

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Lunna [17]
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