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vesna_86 [32]
3 years ago
15

A line contains (4,2) and (0,-1). What is the equation line?

Mathematics
2 answers:
Dafna11 [192]3 years ago
8 0

Answer:

B.

Step-by-step explanation:

densk [106]3 years ago
7 0
The answer is B. Y= 3/4x-1
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Plz help I have been struggling on this one
tamaranim1 [39]

the first answer is 93000000 and the second answer is 240000

4 0
3 years ago
A company's current stock price is $50.00 and its most recent dividend was $2.00 per share. Since analysts estimate the company
4vir4ik [10]

Answer:

Expected rate of return  =7.1% (Approx.)

Step-by-step explanation:

Given:

Current stock price = $50

Divided d = $2

Growth rate g = 5 %

Find:

Expected rate of return

Computation:

Expected rate of return = D(1+g)/Current Price + g

Expected rate of return = [2(1+5%)/50] + 5%

Expected rate of return  =7.1% (Approx.)

6 0
3 years ago
A tobacco company claims that the amount of nicotene in its cigarettes is a random variable with mean 2.2 and standard deviation
Aleksandr-060686 [28]

Answer:

0% probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 2.2, \sigma = 0.3, n = 100, s = \frac{0.3}{\sqrt{100}} = 0.03

What is the approximate probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true?

This is 1 subtracted by the pvalue of Z when X = 3.1. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{3.1 - 2.2}{0.03}

Z = 30

Z = 30 has a pvalue of 1.

1 - 1 = 0

0% probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true.

4 0
3 years ago
Antonia buys a box of 36 soft pretzels she wants to distribute them evenly between her , and her 8 friends and her three brother
kirza4 [7]

Answer:

4

Step-by-step explanation:

36 pretzels divided by 9 people (Antonia + 8 friends) = 4 per person

36 / 9 = 4

4 0
3 years ago
Write an equation for the line passing through the points (-5,15) and (20,25). Show how you found your answer.
olasank [31]

The point-slope form:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (-5, 15) and (20, 25). substitute:

m=\dfrac{25-15}{20-(-5)}=\dfrac{10}{25}=\dfrac{2}{5}\\\\y-15=\dfrac{2}{5}(x-(-5))\\\\y-15=\dfrac{2}{5}(x+5)\qquad|\text{use distributive property}\\\\y-15=\dfrac{2}{5}x+2\qquad|\text{add 15 from both sides}\\\\y=\dfrac{2}{5}x+17\qquad|\text{multiply both sides by 5}\\\\5y=2x+85\qquad|\text{subtract 2x from both sides}\\\\-2x+5y=85\qquad|\text{change the signs}\\\\2x-5y=-85

Answer:

point-slope form: y-15=\dfrac{2}{5}(x+5)

slope-intercept form: y=\dfrac{2}{5}x+17

standard form: 2x-5y=-85

7 0
3 years ago
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