Answer:
C) 113 m^2
Step-by-step explanation:
diameter/2 =radius = 12/2 = 6
area = 6^2(3.14) = 6x6x3.14 = 113 m^2
Answer:
-11
Step-by-step explanation:
The generic solution to ...
- a + b = sum
- a - b = difference
Can be found by adding the two equations:
(a+b) + (a-b) = (sum) + (difference)
2a = (sum + difference)
a = (sum + difference)/2
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Our particular solution is ...
a = (-44 +22)/2 = -11
The greater of the two numbers is -11.
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The other number is -33.
Answer:
32
Step-by-step explanation:
Step 1: Define
f(x) = 3x² - 5x - 4
g(x) = -4x - 12
Step 2: Find f(g(x))
f(g(x)) = 3(-4x - 12)² - 5(-4x - 12) - 4
f(g(x)) = 3(16x² + 96x + 144) + 20x + 60 + 4
f(g(x)) = 48x² + 288x + 432 + 20x + 64
f(g(x)) = 48x² + 308x + 496
Step 3: Find f(g(-4))
f(g(-4)) = 48(-4)² + 308(-4) + 496
f(g(-4)) = 48(16) - 1232 + 496
f(g(-4)) = 768 - 736
f(g(-4)) = 32
Given:
Total number of students = 27
Students who play basketball = 7
Student who play baseball = 18
Students who play neither sports = 7
To find:
The probability the student chosen at randomly from the class plays both basketball and base ball.
Solution:
Let the following events,
A : Student plays basketball
B : Student plays baseball
U : Union set or all students.
Then according to given information,




We know that,



Now,





It means, the number of students who play both sports is 5.
The probability the student chosen at randomly from the class plays both basketball and base ball is


Therefore, the required probability is
.