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prohojiy [21]
3 years ago
12

If you have different movie or audio file types saved to your computer and your computer can only play the OGG format instead of

the MP4 video format, what should you do?
Computers and Technology
1 answer:
galina1969 [7]3 years ago
5 0

Answer:

convert the MP4 format file to the OGG format file                  

Explanation:        

An OGG file is a compressed audio file of Ogg Vorbis that is used for holding audio data. It is a free and an open container file format which is maintained by Xiph.Org Foundation. OGG format file can multiplex independent streams of video, text, audio and meta data.

The OGG file has better sound quality and characteristics than a MP3 or MP4 files. The MP4 file format can be converted into OGG format file if the files are saved in different formats in the computer which can play only OGG format.

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Gimme Shelter Roofers maintains a file of past customers, including a customer number, name, address, date of job, and price of
gulaghasi [49]

Answer:

Hence the complete implementation of python code that reads two files and merges them together.

def merge_file(past_file_path,proposed_file_path, merged_file_path):

   past_file_contents=load_file(past_file_path)

   proposed_file_contents=load_file(proposed_file_path)

   proposed_customer_name = []

   for row in proposed_file_contents:

       proposed_customer_name.append(row[1])

   with open(merged_file_path,'w') as outputf:

       outputf.write("Customer Number, Customer Name, Address\r\n")

       for row in proposed_file_contents:

           line = str(row[0]) +", " + str(row[1]) + ", " + str(row[2]) +"\r\n"

           outputf.write(line)

       for row in past_file_contents:

           if row[1] in proposed_customer_name:

               continue

           else:

               line = str(row[0]) + ", " + str(row[1]) + ", " + str(row[2]) + "\r\n"

               outputf.write(line)

       print("Files merged successfully!")

# reads the file and returns the content as 2D lists

def load_file(path):

   file_contents = []

   with open(path, 'r') as pastf:

       for line in pastf:

           cells = line.split(",")

           row = []

           for cell in cells:

               if(cell.lower().strip()=="customer number"):

                   break

               else:

                   row.append(cell.strip())

           if  len(row)>0:

               file_contents.append(row)

   return file_contents

past_file_path="F:\\Past Customer.txt"

proposed_file_path="F:\\Proposed Customer.txt"

merged_file_path="F:\\Merged File.txt"

merge_file(past_file_path,proposed_file_path,merged_file_path)

8 0
3 years ago
You have been hired to set up a network for XYZ Enterprises. What factors will you consider to determine the type of network nee
Margarita [4]

Answer:

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Explanation:

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Answer:

See Explaination

Explanation:

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ORDER BY SumOFInvoices desc;

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Explanation:

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