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Tasya [4]
2 years ago
11

Which number line would best model the quotient 3/4 divided by 6?​

Mathematics
1 answer:
slava [35]2 years ago
6 0
I think it’s D I hope this helps!!!
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Triangles H J K and L M N are shown. The triangles have identical side lengths and angle measures. Triangle H J K is slightly lo
Hitman42 [59]

Answer:

The answer is b : translate K to N and reflect across the line containing JK

Step-by-step explanation:

I just took the quiz

4 0
3 years ago
I just need to make sure this is correct for a test 6x² - 3x when x=5. my answer was 135
Allushta [10]

Answer:

135 is the correct answer

Step-by-step explanation:

6x^2-3x

substitution

x=5

6* (5*5) -3*5

6*25-3*5

150-15= 135

7 0
3 years ago
Read 2 more answers
William runs at a constant speed of 8 miles per hour. Running at this constant speed, it takes William 75 seconds to run from hi
pav-90 [236]

Answer:

0.16 miles

Step-by-step explanation:

5 0
3 years ago
Solve the given system of equations.<br> - 3a = 36<br> 10a + 3c = 9<br> 2b + 50 = 23
Elodia [21]

Answer:

Solve using the substitution method! Answer down below:)

Step-by-step explanation:

(a,b,c) = ( -12, -27/2,43)

Hope it helps:)

5 0
3 years ago
5. Find the general solution to y'''-y''+4y'-4y = 0
CaHeK987 [17]

For any equation,

a_ny^(n)+\dots+a_1y'+a_0y=0

assume solution of a form, e^{yt}

Which leads to,

(e^{yt})'''-(e^{yt})''+4(e^{yt})'-4e^{yt}=0

Simplify to,

e^{yt}(y^3-y^2+4y-4)=0

Then find solutions,

\underline{y_1=1}, \underline{y_2=2i}, \underline{y_3=-2i}

For non repeated real root y, we have a form of,

y_1=c_1e^t

Following up,

For two non repeated complex roots y_2\neq y_3 where,

y_2=a+bi

and,

y_3=a-bi

the general solution has a form of,

y=e^{at}(c_2\cos(bt)+c_3\sin(bt))

Or in this case,

y=e^0(c_2\cos(2t)+c_3\sin(2t))

Now we just refine and get,

\boxed{y=c_1e^t+c_2\cos(2t)+c_3\sin(2t)}

Hope this helps.

r3t40

5 0
3 years ago
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