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Verdich [7]
3 years ago
9

The probability that you roll a 3 on a six-sided die is start fraction one over six end fraction. The probability that you flip

a coin that lands on tails is start fraction one over two end fraction. The probability that you roll a 3 on a six-sided die and you flip a coin that lands on tails is start fraction one over 12 end fraction. What is the probability of flipping a coin and it landing on tails, given that you rolled a 3 on a six-sided die? Are these two events independent?
Mathematics
1 answer:
valentinak56 [21]3 years ago
5 0
Seems like a trick question to me, I think what this question is asking is "If you roll a 3 on a die, what is the chance of getting tails on a coin." The answer would then be 1/2 (one over two) and the events are independent because rolling a 3 on a die doesn't affect the chances of getting tails on a coin.
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Please help thx a bunch
kirza4 [7]
A.
2/3A=-24
time both sides by 3/2
A=-72/2
A=-36

B.
20=-B/0.2
times both sides by 0.2
4=-B
times -1
-4=B


distance between 2 points x and y is |x-y|

so
distance between A and B is distance between -4 and -72 or
|-72-(-4)|=|-72+4|=|-68|=68
the distance is 68
4 0
3 years ago
Sarah was driving at 50 mph ( miles per hour) and went a distance of 100 miles. How long did it take Sarah to drive that distanc
Ira Lisetskai [31]

Answer:

It took her two hours

Step-by-step explanation:

100 miles  divided by 50mph =2 hours

hope it helps!

4 0
2 years ago
Read 2 more answers
Find the length of the segment indicated.
Goryan [66]

Answer:

I think the answer is 12.5

4 0
3 years ago
HELP PLEASE URGENT!!!!
loris [4]
<span>Equations:
g + b + 0 = 1500
g + 0 + r = 750
g + b + r = 2000
============
</span><span>g = 250
b = 1250
r = 500
============
Happy Valentines :)</span>
4 0
3 years ago
Which are the solutions of the quadratic equation x^2=-5x-3
frutty [35]
The correct answer would be \frac{-5 +/-  \sqrt{13} }{2}

In order to solve for this you must first get the equation equal to 0. 

<span>x^2=-5x-3 ----> add 5x to both sides. 
x^2 + 5x = -3 ----> add 3 to both sides.
x^2 + 5x + 3 = 0

Now knowing this we can use the coefficients of each one in descending order of power as a, b and c. 

a = 1 (because it is the coefficient to x^2)
b = 5</span> (because it is the coefficient to x)
c = 3 (because it is the end number)

Now we can plug these values into the quadratic equation. 

\frac{-b +/-  \sqrt{b^{2} - 4ac } }{2a}

\frac{-5 +/- \sqrt{5^{2} - 4(3)(1) } }{2(1)}

\frac{-5 +/- \sqrt{13} }{2}

And those would be your two answers.
5 0
3 years ago
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