Remember that the radicand (the area under the root sign) must be positive or zero for a radical with an even index (like the square root or fourth root, for example). This is because two numbers squared or to the fourth power, etc. cannot be negative, so there are no real solutions when the radicand is negative. We must restrict the domain of the square-root function.
If the domain has already been restricted to

, we can work backwards to add 11 to both sides. We see that

must be under the radicand, so the answer is
A.
Answer:
8/15
Step-by-step explanation:
4/5 times 2/3
First we have to assume that each quarter touched each other. Hence the area of the table not covered by the coins (A) is equal to the total area of the table (At) minus the total area of the coins (Ac). Coins are circle, so

and r =24.26mm. The area of one coin is then 1848.98mm^2. Hence the equation is A = At - xAc where x is the number of coins.
Move the 11x to the left and the +54 to the right. Their signs will flip:
14x-11x = 96-54
3x = 42
x = 14