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ad-work [718]
2 years ago
10

PLEASE HELP!

Mathematics
1 answer:
adelina 88 [10]2 years ago
3 0

Answer:

A rectangle is bounded by the x-axis and the semicircle y = √(25 - x²). What length and width should the rectangle have so that its area is a maximum?

Step-by-step explanation:

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A home pregnancy test is not always accurate. suppose the probability that the test indicates that a woman is pregnant when she
Gnom [1K]
Set Events:
T=tests positive~T=tests negativeP=subject is pregnant~P=subject is not pregnant
We are givenP(T n ~P)=0.02P(~T n P)=0.03P(P)=0.7
recall by definition of conditional probabilityP(A|B)=P(A n B)/P(B)

Need to find P(P|~T)
First step: make a contingency diagram of probabilities (intersection, n)
          P       ~P       sum 
T       0.67   0.02     0.69=P(T) 
~T     0.03   0.28     0.31=P(~T) 
sum   0.70  0.30     1.00
      =P(P)  =P(~P)

therefore
P(P|~T)=P(P n ~T)/P(~T)=0.03/0.31   [ both read off the contingency table ]
=0.0968

4 0
3 years ago
3x+2y=6 and y=-3/2x+5
love history [14]
In order to solve for parallel, perpendicular, or neither, you have to look at the slope.

If the slope is the same for both equations, it is most likely parallel.
If it's the reciprocal (Where you flip the number and add change the signs. For example, the reciprocal of 1/2 is -2)
If the slope is not the same or the reciprocal, then it is neither. 

So for the first equation, your slope is:
3x+2y=6
2y=-3x+6
y=-3/2x+3      The equation y=mx+b can help you here, where m is the slope.
Your slope is -3/2

For the second equation, your slope is -3/2 since y=-3/2x+5 is already in y=mx+b form and m is the slope.

Since both slopes are -3/2, then you have parallel equations!

(Be careful though, sometimes it will have the same slope but there will also be the same y-intercept. If that happens, it's no longer parallel, but it's the same equation. Such as y=-3/2x+1 and y=-3/2x+1. In this case there will be infinite solutions, but parallel equations have no solutions.)

I hope this helps!! Please ask if you have more questions!
6 0
3 years ago
A building is known to be 192 feet tall. A ball is dropped from the top of the building. In how many seconds will the ball hit t
Archy [21]

Answer:

  • h = 0 when the ball hits the ground
  • about 3.464 seconds

Step-by-step explanation:

The formula gives h = 192 when t=0, so we assume that h represents the height above the ground. The ball will have a height of 0 when it hits the ground.

__

Using that in the equation, we can solve for t.

  0 = 192 -16t^2

  0 = 12 -t^2 . . . . . . divide by 16

  t^2 = 12 . . . . . . . . add t^2

  t = √12 = 2√3 ≈ 3.464 . . . . take the square root

It will take 2√3 seconds, about 3.464 seconds, for the ball to hit the ground.

5 0
3 years ago
If (9 to the 2nd power)p = 9 to the 8th power , what is the value of p?
Novay_Z [31]

(9^2)^p=9^8\\\\9^{2p}=9^8\\\\2p=8\\\\p=4

3 0
3 years ago
Read 2 more answers
HELP PLEASE ILL VENMO THE FIRST PERSON WHO ANSWERS
BaLLatris [955]

Answer:

y=2p+9   i really hope this helps and you dont have to venmo me anything but i had to hurry because i have a quiz and i have to go. bye. hope this helped

Step-by-step explanation:

4 0
3 years ago
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