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Anika [276]
3 years ago
14

Which shows the use of a credit card

Mathematics
1 answer:
kotykmax [81]3 years ago
7 0
C is what you do when credit cards are involved.
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What is the quotient of (x4 + 10x3 + 21x2 + 6x – 8) ÷ (x + 2)? Question 8 options: A) x3 + 8x2 + 5x – 4 + 2∕x + 2 B) x3 + 8x2 +
ANTONII [103]

Answer: C

Step-by-step explanation: Hope this help :D

4 0
3 years ago
A child's wading pool has a diameter of 7 feet an pool has a diameter of 7 feet and is 8 inches deep . How many gallons of water
Leno4ka [110]
7x8 do that work..... n
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3 years ago
Find the intercepts and range of the function f(x)=x^2-6x+8. There will be two X-intercepts and one y-intercept. Range must be f
klio [65]
X=(4,0) (2,0)

y=(0,8)
6 0
3 years ago
PLEASE HELP!!!!
Mazyrski [523]
<h3>Answer:   A.  18</h3>

===========================================================

Explanation:

The set A U B represents the list of items that are either in set A, set B or both sets at the same time. The "U" is the union symbol.

Set A U B looks like this

A U B = {-10, 8, 12, 26, 29,   -8, - 1,5, 26, 36}

I basically started with set A, then tacked on the stuff in set B shown in bold.

From here, we toss out the duplicate item 26 and we can optionally sort the set

A U B = {-10, -8, -1, 5, 8, 12, 26, 29, 36}

We see that the number 18 is not in this final set, which is why choice A is the answer.

--------------------

Put another way: the number 18 is neither in set A nor set B, so it cannot be in set A U B.

Something like -10 is in set A, so it's going to be in set A U B as well. We can rule out choice B for this reason. Choices C and D follow a similar idea as choice B.

4 0
3 years ago
Factor: 10x^2-15x=0 ?
e-lub [12.9K]

Like every quadratic equation

ax^2+bx+c=0

where c=0

ax^2+bx=0

we can factor out x

x(ax+b)=0

And find the two solutions

x=0,\quad x=-\dfrac{b}{a}

In this case, the solutions are

x=0,\quad x=\dfrac{3}{2}

If you know that x_1,\ x_2 are the solutions to the quadratic equation

ax^2+bx+c=0

then you can factor the poynomial as

a(x-x_1)(x-x_2)

So, in this case, you have

10x^2-15x = 10(x-0)\left(x-\dfrac{3}{2}\right)=10x\left(x-\dfrac{3}{2}\right)

8 0
4 years ago
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