one way is to solve for the invers of the first function
remembe, to solve, replace f(x) or g(x) with y, switch x and y, solve for y and replace it with f⁻¹(x)
A.
f(x)=x/2+8
y=x/2+8
x=y/2+8
x-8=y/2
2x-16=y
f⁻¹(x)=2x-16
nope, not A
B.
f(x)=3x³+16
y=3x³+16
x=3y³+16
x-16=3y³
(x-16)/3=y³
∛((x-16)/3)=y
f⁻¹(x)=∛((x-16)/3)
nope, not the same
not B
C.
f(x)=18/x-9
y=18/x-9
x=18/y-9
x+9=18/y
y(x+9)=18
y=18/(x+9)
f⁻¹(x)=18/(x+9)
correct, the answer is C
answer is C
Answer:
36 erasers
Step-by-step explanation:
Let number of erasers be e
let number of rulers be r
We can write:
e + r = 70
and
After giving away, he has
Erasers: 2/3e
Rulers: r - 10
These two are equal, so we can write and solve:
2/3e = r - 10
2/3e + 10 = r
Putting this in initial equation, we have:
e + (2/3e + 10) = 70
5/3e + 10 = 70
5/3 e = 60
e = 36
And rulers is:
r = 2/3(36) + 10 = 34
Hence, he had 36 erasers in the beginning
Answer:
0.16
Step-by-step explanation:
1paise = 1/100rupee
so, 16 paise = 16/100
16/100= 0.16
Which value in this data set is an outlier? 4, 5, 1, 7, 4, 5, 8, 9, 6, 5, 4, 9, 7
omeli [17]
1 is your answer
Note that all the other numbers are inbetween 4 and 9. 1 however, is outside the amount, therefore, your outlier is 1
hope this helps
I THINK IT C
I REALLY TRIED
HOPE I HELPED
