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KengaRu [80]
2 years ago
6

W

align="absmiddle" class="latex-formula">
259  \times 55
help me with this math pls​
Mathematics
1 answer:
krek1111 [17]2 years ago
3 0
This is your answer and for the multiplication I gave it to you step by step

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Find an equation for the line perpendicular to 4x+12y=72 and goes through the point (-9,6)
il63 [147K]

Answer:

Step-by-step explanation:

Given the equation

4x+12y=72

The equation of a line can written as

y=mx+c

Where m is the slope

And c is the intercept on y axis

Then, we need to write the equation given in the form of equation of a line (y=mx+c), by making y subject of the formula

4x+12y=72

12y=-4x+72

Divide through by 12

y=-4x/12 + 72/12

y=-⅓x+6

Then, comparing with equation of a line shows that

m=-⅓ and c=6

So we need to get another linen that is perpendicular to this line and passes through the point (-9,6)

The slope of the line perpendicular to another line is given as

m1=-1/m2

Then, m1=-1÷-⅓

Then, the slope of the perpendicular line is 3

Then, m=3

So apply this to equation of the line

y=mx+c

Then, y=3x+c

So to know c, we will insert the point given(-9,6), x=-9 and y=6

y=3x+c

6=3(-9)+c

6=-27+c

Then, c=6+27

c=33

Then, the equation of line becomes

y=3x+33

7 0
3 years ago
A bookstore packs 6 books in a box. The total weight of the books 14 1/4 pounds. If each book has the same weight, what is the w
Aleks04 [339]

Answer:

2.375 or 2 3/8

Step-by-step explanation:

You want to do total weight over total number of items.

14 1/4 / 6 books = 2.375

8 0
3 years ago
Read 2 more answers
An Eastbound train (E) traveling 95 mph and a Westbound train (W) traveling 110 mph leave the same train station at different ti
Simora [160]

Answer:

The system of linear equations that can be used to determine the time that each of the trains has been traveling is:

E + W = 4 ....... Equation 1

95 E + 110W = 400  ......Equation 2

Hence,

An Eastbound train has been travelling for =  (E) = 2.67 hours

A Westbound train has been travelling for =  (W) = 1.33 hours

Step-by-step explanation:

An Eastbound train (E) traveling 95 mph and a Westbound train (W) traveling 110 mph leave the same train station at different times. After 4 hours, they are 4 00 miles apart. Which system of linear equations can be used to determine the time that each of the trains has been traveling?

Speed = Distance/Time

Distance = Speed × Time

Let the time

An Eastbound train =  (E)

A Westbound train =  (W)

E + W = 4 hours ....... Equation 1

95mph × E + 110mph × W = 400 miles

95 E + 110W = 400 miles ......Equation 2

The system of linear equations that can be used to determine the time that each of the trains has been traveling is:

E + W = 4 ....... Equation 1

95 E + 110W = 400  ......Equation 2

E = 4 - W

We substitute 4 - W for E in Equation 2

95 (4 - W) + 110W = 400  

380 - 95W + 110W = 400

Collect like terms

95W - 110W = 400 - 380

15W = 20

W = 20/15

W = 1.3333333333 hours

≈ 1.33 hours

E = 4 - W

E = 4 - 1.33 hours

E = 2.67 hours

Therefore,

An Eastbound train has been travelling for =  (E) = 2.67 hours

A Westbound train has been travelling for =  (W) = 1.33 hours

8 0
3 years ago
How can you get equation b from equation A. 3(x+2)=18 B. X+2=18
Rzqust [24]

Answer:

We start with the equation:

A: 3*(x + 2) = 18

And we want to construct equation B:

B: X + 2 = 18

where I suppose that X is different than x.

Because in both equations the right side is the same thing, then the left side also should be the same thing, this means that:

3*(x + 2) = X + 2

Now we can isolate the variable x.

(x + 2) = (X + 2)/3

x = (X + 2)/3 - 2

Then we need to replace x by  (X + 2)/3 - 2 in equation A, and we will get equation B.

Let's do it:

A: 3*(x + 2) = 18

Now we can replace x by =  (X + 2)/3 - 2

3*( (X + 2)/3 - 2 + 2) = 18

3*(  (X + 2)/3 ) = 18

3*(X + 2)/3 = 18

(X + 2) = 18

Which is equation B.

3 0
3 years ago
In the figure,BC andAD are line segments. What is the sum of x and y?
Alika [10]
Can you please post the image.
7 0
3 years ago
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