Answer:
2√5
Step-by-step explanation:
The radius is the distance from the center to a point anywhere along the edge of the circle. To find the distance between these two points, use the distance formula.

The statements that are correct are A and E. A because the y-intercept for y=5x+12 is 12 and the table of values it is 5. E is correct because the rate of change for the table of values is 24 and y=5x+12, it is 5.
we know there are 180° in π radians, how many degrees then in -3π/10 radians?
![\bf \begin{array}{ccll} degrees&radians\\ \cline{1-2} 180&\pi \\\\ x&-\frac{3\pi }{10} \end{array}\implies \cfrac{180}{x}=\cfrac{\pi }{~~-\frac{3\pi }{10}~~}\implies \cfrac{180}{x}=\cfrac{\frac{\pi}{1} }{~~-\frac{3\pi }{10}~~} \\\\\\ \cfrac{180}{x}=\cfrac{\pi }{1}\cdot \cfrac{10}{-3\pi }\implies \cfrac{180}{x}=-\cfrac{10}{3}\implies 540=-10x\implies \cfrac{540}{-10}=x \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill -54=x~\hfill](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bccll%7D%20degrees%26radians%5C%5C%20%5Ccline%7B1-2%7D%20180%26%5Cpi%20%5C%5C%5C%5C%20x%26-%5Cfrac%7B3%5Cpi%20%7D%7B10%7D%20%5Cend%7Barray%7D%5Cimplies%20%5Ccfrac%7B180%7D%7Bx%7D%3D%5Ccfrac%7B%5Cpi%20%7D%7B~~-%5Cfrac%7B3%5Cpi%20%7D%7B10%7D~~%7D%5Cimplies%20%5Ccfrac%7B180%7D%7Bx%7D%3D%5Ccfrac%7B%5Cfrac%7B%5Cpi%7D%7B1%7D%20%7D%7B~~-%5Cfrac%7B3%5Cpi%20%7D%7B10%7D~~%7D%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B180%7D%7Bx%7D%3D%5Ccfrac%7B%5Cpi%20%7D%7B1%7D%5Ccdot%20%5Ccfrac%7B10%7D%7B-3%5Cpi%20%7D%5Cimplies%20%5Ccfrac%7B180%7D%7Bx%7D%3D-%5Ccfrac%7B10%7D%7B3%7D%5Cimplies%20540%3D-10x%5Cimplies%20%5Ccfrac%7B540%7D%7B-10%7D%3Dx%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%20-54%3Dx~%5Chfill)
The question is somewhat poorly posed because the equation doesn't involve <em>θ</em> at all. I assume the author meant to use <em>x</em>.
sec(<em>x</em>) = csc(<em>x</em>)
By definition of secant and cosecant,
1/cos(<em>x</em>) = 1/sin(<em>x</em>)
Multiply both sides by sin(<em>x</em>) :
sin(<em>x</em>)/cos(<em>x</em>) = sin(<em>x</em>)/sin(<em>x</em>)
As long as sin(<em>x</em>) ≠ 0, this reduces to
sin(<em>x</em>)/cos(<em>x</em>) = 1
By definition of tangent,
tan(<em>x</em>) = 1
Solve for <em>x</em> :
<em>x</em> = arctan(1) + <em>nπ</em>
<em>x</em> = <em>π</em>/4 + <em>nπ</em>
(where <em>n</em> is any integer)
In the interval 0 ≤ <em>x</em> ≤ 2<em>π</em>, you get 2 solutions when <em>n</em> = 0 and <em>n</em> = 1 of
<em>x</em> = <em>π</em>/4 <u>or</u> <em>x</em> = 5<em>π</em>/4