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mote1985 [20]
4 years ago
8

Consider a game in which players roll a number cube to determine the number of points earned. If a player rolls a prime number,

that many points will be added to the player’s total. Any other roll will be deducted from the player’s total. What is the expected value of the points earned on a single roll in this game?
Mathematics
1 answer:
Svetllana [295]4 years ago
3 0
The expected value of the points earned on a single roll in the game would take into account the probability of the numbers of the cube and whether or not they're prime. If the cube is a dice with numbers 1 to 6, then the expected value of the points would be:
P = 1(1/6) + 2(1/6) + 3(1/6) - 4(1/6) + 5(1/6) - 6(1/6)
P = 1/6 or 0.1667
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3 years ago
How are we supposed to solve this question!?​
VashaNatasha [74]

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use pythagorean's theorem; x=6

Step-by-step explanation:

a^2 + b^2 = c^2

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6 0
3 years ago
Read 2 more answers
In a sample of 679 new websites registered on the Internet, 42 were anonymous (i.e., they shielded their name and contact inform
Semmy [17]

Answer:

95% Confidence interval:  (0.0429,0.0791)      

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 679

Number of anonymous websites, x = 42

\hat{p} = \dfrac{x}{n} = \dfrac{42}{679} = 0.0618

95% Confidence interval:

\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

z_{critical}\text{ at}~\alpha_{0.05} = \pm 1.96

Putting the values, we get:

0.0618\pm 1.96(\sqrt{\dfrac{0.0618(1-0.0618)}{679}}) = 0.0618\pm 0.0181\\\\=(0.0429,0.0791)

is the required confidence interval for proportion of all new websites that were anonymous.

8 0
3 years ago
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